Mixed numbers between 5 and 7, with an interval of 1 / 3 between each pair of mixed numbers

Mathematics

2 answers:

SpyIntel [72]2 years ago

8 0

5 1/3, 5 2/3, 6 1/3, 6 2/3....mixed numbers between 5 and 7.....intervals of 1/3

Harman [31]2 years ago

5 0

Answer:

$5,5\frac{1}{3},5\frac{2}{3},....6\frac{1}{3},6\frac{2}{3},....7$

Step-by-step explanation:

To find : Mixed numbers between 5 and 7, with an interval of $\frac{1}{3}$ between each pair of mixed numbers ?

Solution :

Mixed numbers between 5 and 7.

The interval is $\frac{1}{3}$ between each pair of mixed numbers.

So, The number form as

$5,5+\frac{1}{3},5+\frac{2}{3},....6+\frac{1}{3},6+\frac{2}{3},....7$

In mixed fraction,

$5,5\frac{1}{3},5\frac{2}{3},....6\frac{1}{3},6\frac{2}{3},....7$

Therefore, The mixed numbers between 5 and 7, with an interval of $\frac{1}{3}$ between each pair of mixed numbers are

$5,5\frac{1}{3},5\frac{2}{3},....6\frac{1}{3},6\frac{2}{3},....7$

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After four years of college, Erica has to start paying off all her student loans. Her first payment is due at the end of this mo

tatiyna

Answer:

Therefore, the approximate monthly payment is $548.85

Step-by-step explanation:

The amount of student loans Erica currently has = $34,006.00

The duration over which Erica is to pay back the loan = 7 years

The annual interest rate for the loan = 9.1%

Therefore, we have the geometric sequence formula is given as follows;

$A_n = P( 1 + r)^n - M \times \left [ \dfrac{(1 + r)^n-1}{r} \right ]$

Where;

M = The monthly payment

P = The initial loan balance = $34,006.00

r = The annual interest rate = 9.1%

n = The number of monthly payment = 7 × 12 = 84

Aₙ = The amount remaining= 0 at the end of the given time for payment

Substituting the values into the above formula, , we get;

$0 = 34006 \times \left ( 1 + \dfrac{0.091}{12} \right )^{84} - M \times \left [ \dfrac{\left (1 + \dfrac{0.091}{12} \right )^{84}-1}{\dfrac{0.091}{12} } \right ]$

$M = \dfrac{34006 \times \left ( 1 + \dfrac{0.091}{12} \right )^{84} }{\left [ \dfrac{\left (1 + \dfrac{0.091}{12} \right )^{84}-1}{\dfrac{0.091}{12} } \right ]} \approx 548.85$