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vichka [17]
2 years ago
6

A direct variation function contains the points (–8, –6) and (12, 9). Which equation represents the function? y = –4/3x y = –3/4

x y =3/4x y = 4/3x
Mathematics
1 answer:
Roman55 [17]2 years ago
8 0

Answer:

We need to get the slope first

m=Y2-Y1/X2-X1

=9-(-6)/12-(-8)

=15/20

=3/4

so the answer is the one with 3/4 slope that is Y=3/4x

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In Exercises 15-18, find the measure of the exterior angle.​
valina [46]

Answer:

The measure of the exterior angle is 92 degrees

Step-by-step explanation:

Problem 16)

we know that

An exterior angle of a triangle is equal to the sum of the opposite interior angles

so

In this problem

(2x-2)\°=x\°+45\°

solve for x

2x-x=45+2

x=47\°

Find the measure of the exterior angle

(2x-2)\°=(2(47)-2)=92\°

6 0
2 years ago
Determine the product: (46.2 × 10–1) ⋅ (5.7 × 10–6). Write your answer in scientific notation.
lianna [129]

Answer:

A

Step-by-step explanation:

10-6 X 10-1 = 10-7

5.7*46.2=263.34

263.34=2.6334 x 10^2

10^2 x 10^-7 = 10^-5

so

=2.6334 x 10-5

7 0
2 years ago
Carlos biked StartFraction 139 over 8 EndFraction miles on Saturday and StartFraction 135 over 7 EndFraction miles on Sunday. On
melomori [17]

Answer:

Carlos rode further than on Saturday by 107/56 miles.

Step-by-step explanation:

i did the quiz lol

7 0
2 years ago
Read 2 more answers
The equation y = 5.78 • 1.15x fits the graph of stock XYZ over the past month with an r-value of .9918. How much do you think XY
lilavasa [31]
Not sure if this is right or not, but I chose 125.11 after I typed in the equation, haven’t used R-value at all. Will comment if correct — APEX
8 0
2 years ago
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General solution of equation sin x + sin 5x = sin 2x + sin 4x is
zaharov [31]

Answer:

x=nπ3, n∈I

Step-by-step explanation:

sin x + sin 5x = sin 2x + sin 4x

⇒⇒   2 sin 3x cos 2x = 2 sin 3x cos x

⇒⇒   2 sin 3x(cos 2x - cos x) = 0

⇒    sin 3x=0 ⇒ 3x=nπ ⇒ x=nπ3⇒    sin 3x=0 ⇒ 3x=nπ ⇒ x=nπ3 , n∈I, n∈I

or    cos 2x−cos x=0 ⇒ cos 2x=cos xcos 2x-cos x=0 ⇒ cos 2x=cos x

⇒   2x=2nπ±x  ⇒  x=2nπ, 2nπ3⇒   2x=2nπ±x  ⇒  x=2nπ, 2nπ3 , n∈I, n∈I

But solutions obtained by x=2nπx=2nπ , n∈I, n∈I or x=2nπ3x=2nπ3 , n∈I, n∈I are all involved in x=nπ3x=nπ3 , n∈I

7 0
2 years ago
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