Answer:
consistent phrasing is missing
Explanation:
If you will note carefully, the bullets are not in correct format. The model is missing. The correct one is as below.
Risks
The correct form of presentation is as below:
1. Risks
a. employees
a. physical illness
b. mental illness
c. death
2. Customers
a. complaints
b. downtime
3. Benefits
However, the content seems to be complete now, and hence not anything else is required. And since its not something very tough to decide to go with, bite the bullet is certainly not an issue.
Answer:
for(String s:words)
if(s.endsWith("ing"))
System.out.println(s);
Explanation:
Create an enhanced for loop that iterates through the words array
Check if an element in words ends with "ing" using endsWith() method (Since it is said that strings are lowercase letters, we do not need to check it)
If you find one that ends with "ing", print the element
Answer:
C++ code given below with appropriate comments
Explanation:
pattern.cpp
#include<iostream>
using namespace std;
void printCross(int n)
{
int i,j,k;
if(n%2) //odd number of lines
{
for(int i=n;i>=1;i--)
{
for(int j=n;j>=1;j--)
{
if(j==i || j==(n-i+1))
cout<<j;
else
cout<<" ";
}
cout<<"\n";
}
}
else //even number of lines
{
for(int i=1;i<=n;i++)
{
for(int j=1;j<=n;j++)
{
if(j==i || j==(n-i+1))
{
cout<<" "<<j<<" ";
}
else
cout<<" ";
}
cout<<"\n";
}
}
}
void printForwardSlash(int n)
{
if(n%2)
{
for(int i=n;i>=1;i--)
{
for(int j=n;j>=1;j--)
{
if(j==n-i+1)
{
cout<<j;
}
else
cout<<" ";
}
cout<<"\n";
}
}
else
{
for(int i=1;i<=n;i++)
{
for(int j=1;j<=n;j++)
{
if(j==(n-i+1))
{
cout<<j;
}
else
cout<<" ";
}
cout<<"\n";
}
}
}
void printBackwardSlash(int n)
{
if(n%2) // odd number of lines
{
for(int i=n;i>=1;i--)
{
for(int j=n;j>=1;j--)
{
if(j==i)
{
cout<<j;
}
else
cout<<" ";
}
cout<<"\n";
}
}
else //even number of lines
{
for(int i=1;i<=n;i++)
{
for(int j=1;j<=n;j++)
{
if(j==i)
{
cout<<j;
}
else
cout<<" ";
}
cout<<"\n";
}
}
}
int main()
{
int num;
char ch;
cout<<"Create a numberes shape that can be sized."<<endl;
cout<<"Input an integer [1,50] and a character [x,b,f]."<<endl;
cin>>num>>ch;
if(ch=='x' || ch=='X')
printCross(num);
else if(ch=='f' || ch=='F')
printForwardSlash(num);
else if(ch=='b' || ch=='B')
printBackwardSlash(num);
else
cout<<"\nWrong input"<<endl;
return 0;
}
Document.write()
I'm not sure that this is a method, but I think this is right.
