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ankoles [38]
2 years ago
6

A Rancher is mixing two types of food, Brand X and Brand Y for his cattle. If each serving is required to have 60 grams of prote

in and 30 grams of fat, where Brand A has 15 grams of protein and 10 grams of fat and costs 80 cents per unit, and Brand B contains 20 grams of protein and 5 grams of fat, and cost 50 cents per unit, how much of each type should be used to minimize cost to the Rancher? a. Formulate a linear Programming model for this problem b. Solve this method by using Solver method
Business
1 answer:
irakobra [83]2 years ago
8 0

Answer:

\left \{ {{15Q_a + 20Q_b = 60} \atop {10Q_a + 5Q_b = 30}} \right.

Brand A Q 2.4

Brand B Q 1.2

Explanation:

Using Excel solver:

contrains:

c4 = 60

d4 = 30

solve e4 for min

variable cell b2:b3

a              b        c          d         e

              Q Protein Fat Cost

Brand A 2.4 36         24 1.92

Brand B 1.2 24           6 0.6

                       60         30 2.52

Protein = 60

Fat = 30

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Oil Wells offers 5.65 percent coupon bonds with semiannual payments and a yield to maturity of 6.94 percent. The bonds mature in
FinnZ [79.3K]

Answer:

option (d) $929.42

Explanation:

Data provided in the question:

Coupon bonds payments = 5.65% semiannual

Yield to maturity, r = 6.94% = 0.0694

Face value = $1000

Now,

Coupon bond payments = \frac{5.65\%}{2} × $1,000

= $28.25

market price per bond = Payment × \frac{(1-\frac{1}{(1+\frac{r}{2})^{2n}})}{\frac{r}{2}} + \frac{\textup{face value}}{(1+\frac{r}{2})^{2n}}

Here,

n is the maturity period and 2n is due to the semiannual payments

Thus,

market price per bond = $28.25 × \frac{(1-\frac{1}{(1+\frac{0.0694}{2})^{2\times7}})}{\frac{0.0694}{2}} + \frac{\textup{1,000}}{(1+\frac{0.0694}{2})^{2\times7}}

= $28.25 × 10.942 + 620.3

= $929.42

Hence,

The answer is option (d) $929.42

7 0
2 years ago
Read 2 more answers
Micro, Inc., started the year with net fixed assets of $75,300. At the end of the year, there was $96,700 in the same account, a
Pie

Answer:

$158,730

Explanation:

Mario incoporation started the year with a net fixed assets of $75,300

At the end of the year the net fixed assets was $96,700

The depreciation expense is $13,270

Therefore the company's net capital spending for the year can be calculated as follows

= $96,700+$75,300-$13,270

= $172,000 - $13,270

= $158,730

Hence the company's net capital spending for the year is $158,730

6 0
2 years ago
For the next 2 questions, use the financials of Acme Corporation. After adjusting revenue for accounts receivable and deferred r
Mekhanik [1.2K]

Answer: B. $892.1 million

Explanation:

The Revenue was $939,393 million

When calculating how much cash was generated any increase to the Accounts Receivables is removed from the revenue because it signifies that more sales were made on credit and so have not given the business cash yet.

Any increase in Deferred Revenue must be added because this is Cash that has been given to the business but for accrual purposes cannot be recognized yet. Bottomline however, the Cash has been received.

Increase in Receivables = 309,196 - 221,504

= $87,692 million

Increase in Deferred Revenue= 374,730 - 334,358

= $40,372 million

The Cash generated is therefore;

= 939,393 - 87,692 + 40,372

= $892,073

= $892.1 million

I have attached the Financial Statements of Acme Corporation.

6 0
2 years ago
An investment pays $400 in one year, X amount of dollars in two years, and $500 in three years. The total present value of all t
k0ka [10]

Answer:

X = 789.70

Explanation:

we solve for X considerign each deposit is discounted at the given rate using the lump sum formula:

\frac{Maturity}{(1 + rate)^{time} } = PV

\frac{400}{1.06}+\frac{X}{1.06^2}  +\frac{500}{1.06^3} = 1,500\\X= (1,500 - \frac{400}{1.06} - \frac{500}{1.06^3}) \times 1.06^2

X = 789.7018868

6 0
2 years ago
A plant produces aluminum, facing costs of C(A) = \frac{A^2}{10}, where A is the number of aluminum units produced, and selling
slavikrds [6]

Answer:

$10

Explanation:

We are to account for external costs in production, since we are asked to find optimal tax.

Given:

C(A) = \frac{A^2}{10}

We now have:

C(A) = \frac{A^2}{10} + \frac{A^2}{20}

A represents number of aluminum units produced, let's find A, since the margnal cost is $30.

Thus,

30 = \frac{A}{5} +  \frac{A}{10}

30 = \frac{2A + A}{10}

300 = 3A

A = \frac{300}{3}

A = 100

Let's equate the private marginal cost with the marginal revenue of each unit in order to achieve this amount of produced units with tax, t.

We have:

30 - t = \frac{A}{5}

Substituting 100 for A above, we have:

30 - t = \frac{100}{5}

30 - t = 20

t = 30 - 20

t = 10

Therefore, the socially optimal tax on aluminum is $10 per unit

8 0
2 years ago
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