Question

What would be the results of the following code? int[] array1 = new int[25]; … // Code that will put values in array1 int value = array1[0]; for (int a = 1; a < array1.length; a++) { if (array1[a] < value) value = array1[a]; }

Answer 1

Answer:

'value' contains the minimum value in the array, array1.

Explanation:

In the code:

int[] array1 = new int[25];

…

// Code that will put values in array1

int value = array1[0];

for (int a = 1; a < array1.length; a++) {

   if (array1[a] < value) value = array1[a];

}

We declare an integer array array1 of size 25.

We initialize the variable 'value' to the first element of the array , array1[0].

Then we iterate through the array to update the value whenever the array element is less than the current 'value'.

So eventually value will contain the minima in the original array.

Answer 2

Answer:

value = 0

and every element of array1 is 0.

Explanation:

int[] array1 = new int[25];

Since it is initialized using new keyword.Elements of the array initialized using new are always initialized with 0.So value will become 0 since value of array1[0] is 0 and in the the loop if condition will never gets executed because array1[a] is always 0 that is equal to value.