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scoundrel [369]
2 years ago
5

To be a successful computer systems engineer, you must be proficient in programming languages and operating systems. Similarly,

to be a good animator, you must have good knowledge of the principles of animation. Identify the different skill requirements for computer professionals. Collectively, skills like the ones listed above are skills. These skills refer to the . However, skills are also important, because they relate to the ability to interact and communicate effectively with people.
Computers and Technology
2 answers:
Maslowich2 years ago
6 0

Collectively, skills like the ones listed above are Technical skills. These skills refer to the Knowledge and ability to perform specific tasks. However, Soft skills are also important, because they relate to the ability to interact and communicate effectively with people.

Evgen [1.6K]2 years ago
3 0

Answer:

For the first one, soft, technical, and interpersonal.

Second one, knowledge and ability to perform specific tasks, ability to interact and communicate effectively with people, and ability to work under pressure during adverse situations.

Third one, soft, interpersonal, and leadership.

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For multicore processors to be used effectively, computers must understand how to divide tasks into parts that can be distribute
AnnyKZ [126]

Answer: parallel processing

Explanation:

Parallel processing is the process by which the processor has the capacity to execute parallel instruction at the same time. This is possible only by assigning the different task to the different cores present in the cpu. So a cpu with multiple cores are able to process multiple task as the same time parallel.

8 0
2 years ago
Which XXX and YYY correctly output the smallest values? Vector user Vals contains integers (which may be positive or negative).
liubo4ka [24]

Answer:

The answer is "minVal - userVals.at(0); /userVals.at(i) < minVal  "

Explanation:

In the question, it uses minVal instead of XXX to hold the very first arra(userVal) element, and rather than YYY you choose a conditional statement to check which integer is lower than minVal to index of loop increment. It changes the value of the minVal if the condition is valid. It's completely different if we talk about another situation.

3 0
1 year ago
Sea level is the average level of the sea between high and low tide. It is used as a reference point for measuring elevation, or
SSSSS [86.1K]

Answer:

-8 and 735

Explanation:

Since the sea is a body of water (fluid) it takes the same properties as a fluid does which means filling an area and finding a leveled point. This is why we use the sea as a starting elevation point for Earth's land and it is given a numerical value of 0. Since it starts at 0 any land above Sea Level is in the positives while land below Sea Level is in the negatives. Therefore Since New Orleans is 8 feet below sea level its numerical value elevation is -8. The highest point in Chicago is 735 feet above sea level which makes its numerical value 735

6 0
2 years ago
Read 2 more answers
For any element in keysList with a value greater than 50, print the corresponding value in itemsList, followed by a space. Ex: I
VARVARA [1.3K]

Answer:

import java.util.Scanner;  //mentioned in the question.

public class ArraysKeyValue {  //mentioned in the question.

public static void main (String [] args) {  //mentioned in the question.

final int SIZE_LIST = 4; //mentioned in the question.

int[] keysList = new int[SIZE_LIST]; //mentioned in the question.

int[] itemsList = new int[SIZE_LIST]; //mentioned in the question.

int i; //mentioned in the question.

keysList[0] = 13; //mentioned in the question.                                

keysList[1] = 47; //mentioned in the question.

keysList[2] = 71; //mentioned in the question.

keysList[3] = 59; //mentioned in the question.

itemsList[0] = 12; //mentioned in the question.

itemsList[1] = 36; //mentioned in the question.

itemsList[2] = 72; //mentioned in the question.

itemsList[3] = 54;//mentioned in the question.

// other line to complete the solution is as follows--

for(i=0;i<(keysList.length);i++) //Loop to access all the element of keysList array variable.

    {// open for loop braces

        if(keysList[i]>50) // compare the value of keysList array variable with 50.

        System.out.println(itemsList[i]); // print the value

   }// close for loop braces.

}//  close main function braces.

} //close the class braces.

Output:

72

54

Explanation:

In the solution part--

  1. One loop is placed which moves from 0 to (size-1) of the 'keyslist' array.
  2. Then the 'if' statement is used to check the element of 'keyslist' array, which is greater than 50 or not.
  3. If it is greater, then print the element of item_list array of 'i' index which is also the index of greater value of keyslist array element.

5 0
2 years ago
What is the Gain (dB) of a transmission if the Maximum Data Rate is 1 Gbps and the Bandwidth =7000 MHz? Group of answer choices
denpristay [2]

Answer:

15.420 dB

Explanation:

the Gain (dB) of a transmission if the Maximum Data Rate is 1 Gbps and the Bandwidth =7000 MHz is 15.420 dB.

3 0
2 years ago
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