The feature of technology that allows this to happen is d. reduced latency.
Latency is the amount of time it takes for data to be transmitted in a network. Reduced latency therefore refers to a situation where data is transmitted with speed.
Reduced latency allows:
- better communication
- reduced lag and,
- better gaming
The machine in question is only able to quickly sound the alarm because it has low latency.
In conclusion, we can say that low latency enables the machine above to sound the alarm quickly which means that low latency is important to the safety of that environment.
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Options for this question include:
a. improved bandwidth
b. connection density
c. effective range
d. reduced latency
In this activity Morgan is preparing the digital files to a printer on a DTP project.
Explanation:
DTP project is the creation of documents using page layout on a personal computer. The process of printing digital based images directly to variety of media substrates is known as digital processing.
The digital files like PDFs can be sent directly to digital printing press to print on paper, photo paper, fabric and so on.
They have unique fade rates and different sensitives to the various deterioration mechanisms. DTP is used for graphic designers to create documents.
Answer:
The set is a object of the class 'H' and the setY method is a member of G class which is not called by the object of H class.
Explanation:
- If a user calls the G function which is not a private by the help of H class objects then it can be called. It is because all the public and protected methods of A class can be accessed by the B class if B extends the A-class.
- If any class is extended by the other class then the derived class holds the property of the base class and the public and protected method can be accessed by the help of a derived class object.
- The derived class object can be created by the help of base class like written in the "line 1".
- But the base class can not call the member of the derived class.
Answer:
count = 0;
longest =0;
String myString = new String();
while (input.hasNext()){
myString = input.next();
if (myString.length() == longest) count++;
else
if (myString.length() > longest){
longest = myString.length();
count = 1;
}
}
Explanation:
