Answer:
-3/2
Step-by-step explanation:
Let x be the missing number
- x*
=
- x =
*
inverse 14/25 since it's a fraction
- x =
- x =
write 75 as 25*3 and -28 as -4*7 to simplify
- x =
-4 is left on the top and 6 = 3*2
- x =
- x=
Grace and her dad are planning to attend the state fair. An adult ticket is $15.00. The price of an adult ticket is one half the
1 answer:
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Answer:
(1). y = x ~ Exp (1/3).
(2). Check attachment.
(3). EY = 3(1 - e^-2).
(4). Var[y] = 3(1 - e^-2) (1 -3 (1 - e^-2)) - 36e^-2.
Step-by-step explanation:
Kindly check the attachment to aid in understanding the solution to the question.
So, from the question, we given the following parameters or information or data;
(A). The probability in which attempt to establish a video call via some social media app may fail with = 0.1.
(B). " If connection is established and if no connection failure occurs thereafter, then the duration of a typical video call in minutes is an exponential random variable X with E[X] = 3. "
(C). "due to an unfortunate bug in the app all calls are disconnected after 6 minutes. Let random variable Y denote the overall call duration (i.e., Y = 0 in case of failure to connect, Y = 6 when a call gets disconnected due to the bug, and Y = X otherwise.)."
(1). Hence, for FY(y) = y = x ~ Exp (1/3) for the condition that zero is equal to y = x < 6.
(2). Check attachment.
(3). EY = 3(1 - e^-2).
(4). Var[y] = 3(1 - e^-2) (1 -3 (1 - e^-2)) - 36e^-2.
The condition to follow in order to solve this question is that y = 0 if x ≤ 0, y = x if 0 ≤ x ≤ 6 and y = 6 if x ≥ 6.
The normal distribution curve is shown in the diagram below
<span>The percentage of time that his commute time exceeds 61 minutes is equal to the area under the standard normal curve that lies to the RIGHT of X=61
Standardising X=61 to find z-score
</span>
<span>
from the z-table
</span>
<span>
</span>
<span>The percentage of time that his commute time exceeds 61 minutes is equal to the area under the standard normal curve that lies to the RIGHT of X=61
Standardising X=61 to find z-score
</span>
<span>
from the z-table
</span>
</span>