All categories

2 years ago

How many groups of 1/2 days are in 1 week

Mathematics

2 answers:

SSSSS [86.1K]2 years ago

7 0

Answer:14

Step-by-step explanation:

qwelly [4]2 years ago

6 0

Answer:

There are 14 groups of $\frac{1}{2}$ days are in 1 week.

Step-by-step explanation:

To find : How many groups of $\frac{1}{2}$ days are in 1 week ?

Solution :

We know that,

1 week = 7 days

1 day = $\frac{1}{7}$ week

$\frac{1}{2}$ day = $\frac{1}{2}\times \frac{1}{7}$ week

$\frac{1}{2}$ day = $\frac{1}{14}$ week

i.e. there are 14 groups of $\frac{1}{2}$ days are in 1 week.

You might be interested in

Consider 8x2 - 48x = -104. Write the equation so that x2 – 6x + (blank) = –13 + (blank)

Monica [59]

Answer:

That (blank) is 9.

Step-by-step explanation:

Please write 8x^2 - 48x = -104, with " ^ " indicating exponentiation. Thanks.

This sounds like a perfect example of "completing the square."

First, factor 8x^2 - 48x = -104: 8(x^2 - 6x = -13).

If we focus SOLELY on x^2 - 6x = -13, it's just a little easier to "complete the square." Take half of the coefficient of x (which here is -6), and square that result (which here is (-3)^2, or 9. Now add 9 both sides of x^2 - 6x = -13:

x^2 - 6x + 9 = -13 + 9. Note: The "blank" in the problem statement is 9.

We could go ahead and solve this, tho' we weren't asked to do so. Rewrite x^2 - 6x + 9 as (x - 3)^2:

x^2 - 6x = -13 then becomes (x - 3)^2 = 4. To solve for x, take the sqrt of both sides of this latest result, obtaining x - 3 = plus or minus 2. Add 3 to both sides to isolate x: x = 3 plus or minus 2.

Thus, x = 5 or x = 1.

5 0

2 years ago

Read 2 more answers

Suppose that the universal set is U={1,2,3,4,5,6,7,8,9,10}. Express each of the following subsets with bit strings (of length 10

Vladimir [108]

Answer:

0011100000

1010010001

0111001110

Step-by-step explanation:

As the question is not complete, Here is the complete question.

Suppose that the universal set is U = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}. Express each of these sets with bit strings where the ith bit in the string is 1 if i is in the set and 0 otherwise.

a) {3, 4, 5}

b) {1, 3, 6, 10}

c) {2, 3, 4, 7, 8, 9}.

So, we need to express a) b) and c) into bit strings.

Firstly, number of elements in the universal set represent the number of bits in the bit string.

Secondly, 1 = yes element is present in both universal set as well as in sub set.

0 = No, element is not present in sub set but present in universal set.

Hence, we have:

a) Sub set {3,4,5} = 0011100000 (As there are 3 1's which means only 3,4,5 are present in both universal set and subset.

Similarly,

b) Sub set {1, 3, 6, 10} = 1010010001

c) Sub set {2, 3, 4, 7, 8, 9} = 0111001110

5 0

2 years ago

A high school student volunteers to present a report to the administration about the types of lunches students prefer. He survey

Keith_Richards [23]

<span>Convenience sampling.</span>

6 0

2 years ago

Read 2 more answers

Helena needs 3.5 cups of flour per loaf of bread and 2.5 cups of flour per batch of muffins. She also needs 0.75 cup of sugar pe

telo118 [61]

With the choices you gave, the answer to this question is the first statement, "2 loaves of bread and 4 batches of muffins''. I arrived with the answer through multiplying the amount of flour and sugar required for each loaf of bread and batch of muffins.

4 0

2 years ago

In a lecture demonstration, an object is suspended from a spring scale which reads 8N when the object is in air. The object is t

katovenus [111]

Answer:

a) density of the object is 3995.01, b) the weight scale reads 22N c) the sum individually will be the same with when added together.

Step-by-step explanation:

The weight of the object in air is 8N,

and weight = Mass * acceleration due to gravity = m * 9.81

8/9.81 = 0.815,

upthrust( force acting on the body from the liquid impeding the immersion) on the body when fully submerged = weight in air - weight in water = 8N - 6N =2N

Upthrust = weight of water displaced = 2N = mass * acceleration

2/9.81 = 0.204kg

density of water(1000kg/m^3) = mass of water / volume of water

volume of water displaced = 0.204/1000 = 0.000204m^3 (204cm^3)

volume of water displaced = volume of the solid

density of solid = mass/ volume = 0.815/0.000204 = 3995.01kg/m^3

b) when fully submerge in water the the scale experience according to newton third law of motion ( equal and opposite reaction of forces) additional 2N push so that total weight with the fully submerge solid = 20N + upthrust = 20N + 2N =22N

c) the of two scale reading is before (8N + 20N = 28N) and after (6N + 22N = 28) since there is no loss of matter; the demonstration was in equilibrium.

6 0

2 years ago