Three wax palm trees are kept at different humidity levels inside of a greenhouse for 12 weeks. One tree is left outside in norm
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Answer:
a. Genotype of male parent= BbNn
Genotype of female parent: bbnn
b: Progeny ratio= 1: 1: 1: 1
c: 1/4
Explanation:
a. Genotype of male parent= BbNn
Genotype of female parent: bbnn
b. Gamete formed by the male parent: BN: Bn: bN: bn in 1:1:1:1 ratio.
Gametes formed by female parent: All gametes with "bn" alleles.
c. The probability that the offspring will have a genotype of Bbnn=
Bb x bb= 1/2 Bb: 1/2 bb
Nn x nn= 1/2 Nn: 1/2 nn
Therefore, probability that the offspring will have a genotype of Bbnn= 1/2 Bb x 1/2 nn= 1/2.
