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Alborosie
2 years ago
13

A mutation takes place in a protein-coding gene that changes one codon resulting in a single amino acid replacement. Which type

of replacement is least likely to result in a disruption of protein structure and function?
Biology
1 answer:
nignag [31]2 years ago
3 0
A silent mutation. This is when the new codon will work just as well as the old one without changing the amino acid shape.
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Maintenance of optimal cell functioning requires a balanced cellular environment called
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Select the correct answer from each drop-down menu. Hilda and her family are going on a sailing trip this summer, and Hilda is e
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Answer:

Hilda and her family are going on a sailing trip this summer, and Hilda is especially interested in spotting dolphins. In which zone of the ocean is Hilda most likely to spot dolphins? Hilda and her family are most likely to spot dolphins in the PELAGIC zone. To view shorebirds and crabs, Hilda should move towards the INTERTIDAL zone.

Explanation:

The Pelagic Zone

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Divisions of the Pelagic Zone

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The intertidal zone

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The major attribute of the intertidal zone is that it is immersed with water at high tide and is in exposure to the air at lower limit. The intertidal zone is usually undergoing alterations leading to organisms that are uniquely adapted to strive there.

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5 0
2 years ago
Pseudomonas sp. has a mass doubling time of 2.4 h when grown on acetate. The saturation constant using this substrate is 1.3 g/l
erastova [34]

Answer:

a)  Cell concentration when the dilution rate is one-half of the maximum is  0.598g cell/L

b) the substrate concentration when the dilution rate is 0.8 D_{max}   is 5.2g/l

c) the maximum dilution rate is : 0.41 h⁻¹

d)  the cell productivity at 0.8  D_{max}   is 2.40g cell/L

Explanation:

Given data :

Mass doubling time of Pseudomonas sp. = 2.4 hr

Saturation constant = 1.3 g/L

Cell yield  on acetate = 0.46g cell/g acetate

We are to find;

a. Cell concentration when the dilution rate is one-half of the maximum.

Here, cell yield =amount of cell produced / amount of substrate consumed.

[S] at 0.5D max is determined using the Monod's equation.

Using the formula :

D = \frac {D_{max}[S] }{ks+[S]}

, where D is the dilution rate,

[S] is substrate concentration; &

Ks is the saturation constant.

By replacing the values, we get :

0.5 = \frac{S}{1.3+[S]}

\\\0.65=0.5[S]

[S]=1.3g/L

The cell concentration at 0.5Dmax= cell yield x substrate consumed at 0.5Dmax.

=0.46×1.3

= 0.598g cell/L

b)

Substrate concentration when the dilution rate is 0.8 D_{max}    is calculated as:

D = \frac {D_{max}[S] }{ks+[S]}

0.8=[S]/1.3+[S]

1.04+0.8[S]=[S]

[S]= 5.2g/L

Therefore ,  the substrate concentration when the dilution rate is 0.8 D_{max}   is 5.2g/l

c)

Maximum dilution rate is calculated using the expression D_{max} = \frac{1}{time}

=1/2.4

=0.41 h⁻¹

So, the maximum dilution rate is : 0.41 h⁻¹

d)

The cell productivity at 0.8 D_{max} can be calculated by multiplying the amount  of the cell yield with the amount of the substrate consumed at 0.8D_{max}  

Cell yield = \frac {cell \ productivity \ at \  0.8Dmax}{amount \ of \ substrate\ consumed \at\ 0.8 \D_{max}}

Cell productivity at 0.8 D_{max}    = 0.46 × 5.2

=2.40g cell/L

Therefore, the cell productivity at 0.8  D_{max}   is 2.40g cell/L

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