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zimovet [89]
2 years ago
9

Assume that name has been declared suitably for storing names (like "Misha", "Emily" and "Sofia"). Assume also that stdin is a v

ariable that references a Scanner object associated with standard input Write some code that reads a value into name then prints the message "Greetings, NAME" on a line by itself, where NAME is replaced the value that was read into name. For example, if your code read in "Rachel" it would print out "Greetings, Rachel" on a line by itself.
Computers and Technology
1 answer:
zaharov [31]2 years ago
5 0

Answer:

// program in java.

import java.util.*;

// class definition

class Main

{// main method of the class

public static void main (String[] args) throws java.lang.Exception

{

   try{

    // object to read input

Scanner scr=new Scanner(System.in);

 // ask to enter name

System.out.print("Enter Your name: ");

 // read name from user

String NAME=scr.nextLine();

// print message

System.out.println("Greetings,"+NAME);

     

   }catch(Exception ex){

       return;}

}

}

Explanation:

Read name from user with the help of scanner object and assign it to variable "NAME".Then print a Greetings message as "Greetings,NAME" where NAME will be  replaced with user's input name.

Output:

Enter Your name: Rachel                                                                                                    

Greetings,Rachel

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#Write a function called fancy_find. fancy_find should have #two parameters: search_within and search_for. # #fancy_find should
Inessa05 [86]

Answer:

Here is the Python program:

def fancy_find(search_within , search_for):  # function definition of fancy_find function that takes two parameters

   index = 0  #to store the index of search_within where the search_for string is found

   if search_for in search_within:  #checks if the string search_for is present in string search_within

       sf = search_for[0]  #points to the first character of the search_for

       for sw in search_within:  #iterates through search_within

           if sw == sf:  #if the first character of search_for is equal to the character at sw index of search_within

               if search_within[index:index+len(search_for)] == search_for:  #checks if the value of search_for is found in search_within

                   print(search_for,"found at index",index,"!")  #if above condition is true prints the message "[search_for] found at index [index]!", with [search_for] and [index] replaced by the value of search_for and the index at which it is found

                   return ""  

           index += 1  #increments value of index at each iteration

   print(search_for,"is not found within", search_within)  #if search_for is not found within search_within, prints message "[search_for] was not found within [search_within]!" with the values of search_for and search_within.

   return ""    

#following two statements are used to test the working of above function

print(fancy_find("ABCDEF", "DEF"))  #calls fancy_find() passing "ABCDEF" as search_within and "DEF" as search_for

print(fancy_find("ABCDEF", "GHI")) #calls fancy_find() passing "ABCDEF" as search_within and "GHI" as search_for

Explanation:

The program is well explained in the comments. I will explain the working of the function with the help of an example:

Suppose

search_within = "ABCDEF"

search_for = "DEF"

We have to find if search_for i.e. DEF is present in search_within i.e. ABCDEF

if search_for in search_within statement checks using in operator that if DEF is included in ABCDEF. Here this condition evaluates to true so the next statement sf = search_for[0]  executes which sets the first element of search_for i.e. D to sf. So sf = 'D'

for sw in search_within this statement has a for loop that iterates through ABCDEF and works as following:

At first iteration:

sw contains the first character of search_within  i.e. A

if sw == sf: condition checks if the first character of the search_for i.e. D is equal to sw i.e. A. Its not true so the program control moves to this statement:

index += 1 This increases the value of index by 1. index was initialized to 0 so now it becomes 1. Hence index=1

At second iteration:

sw contains the second character of search_within  i.e. B

if sw == sf: condition checks if the first character of the search_for i.e. D is equal to sw i.e. B Its not true so the program control moves to this statement:

index += 1 This increases the value of index by 1. index was initialized to 0 so now it becomes  2. Hence index=2

At third iteration:

sw contains the third character of search_within  i.e. C

if sw == sf: condition checks if the first character of the search_for i.e. D is equal to sw i.e. C Its not true so the program control moves to this statement:

index += 1 This increases the value of index by 1. index was initialized to 0 so now it becomes  3. Hence index=3

At fourth iteration:

sw contains the third character of search_within  i.e. D

if sw == sf: condition checks if the first character of the search_for i.e. D is equal to sw i.e. D. Its true so so the program control moves to this statement:

  if search_within[index:index+len(search_for)] == search_for:

current value of index=3

len(search_for) returns the length of DEF i.e. 3

So the if condition checks for the search_for in search_within. The statement becomes:

if search_within[3:3+3] == search_for:

search_within[3:3+3]  means from 3rd index position of search_within to 6-th index position of the search_within. This means from 4th element of search_within i.e. D to the last. Hence search_within[3:3+3] is equal to DEF.

search_for = DEF so

if search_within[3:3+3] == search_for: checks if

search_within[3:3+3] = DEF is equals to search_for = DEF

Yes it is true so

print(search_for,"found at index",index,"!") statement is executef which prints the following message:

DEF found at index 3!

This output is because search_for = "DEF" and index=3

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castortr0y [4]

Answer:

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Im still a little confused on the question.

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A large department store has been attaching tags with barcodes to merchandise, and employees use barcode readers to scan merchan
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The department store should consider using RFIDs (Radio Frequency Identification) for tracking inventory. Unlike the wireless barcodes, RFID uses radio waves to communicate with readers. One very common advantage of an RFID is the scanning range. Wireless barcodes, for instance, requires the reader to be close to the barcode before it can see it to scan it. However, RFID systems can scan a tag as long as it is within range. This is important because it reduces wastage of time on labor-intensive processes and increases task speed, convenience, and project turnover.

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