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MA_775_DIABLO [31]
2 years ago
9

A student examining leaf cross sections under a microscope finds many loosely packed cells with relatively thin cell walls. The

cells have numerous chloroplasts. What type of cells are they?
Biology
1 answer:
Ghella [55]2 years ago
3 0

Answer:

The answer is spongy mesophyll.

Explanation:

Between the upper and lower epidermis of a leave, you can find the so called mesophyll tissue which is rich in chloroplasts. There are two types of mesophyll tissue: the palisade and the spongy mesophyll. Whereas the cells of the palisade mesophyll are tightly packed, the cells of the spongy mesophyll are loosely packed.

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Why does the headless horseman carry his head under his arm geometry worksheet?
Serggg [28]

Based on the question above, the best answer would be:

 

That the headless horseman had to hold his head in his arms is because he “wanted to see what’s ahead.”

 

Or a simple geometric equation of SOH CAH TOA would help solve the angle degree.

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2 years ago
In vertebrates with a double-loop circulation as illustrated in Figure 27–4, the loop that passes through the lungs is responsib
egoroff_w [7]
The correct answer among the choices provided is option A. Lung capillaries are responsible for exchanging carbon dioxide for oxygen from the air. Blood that comes from the heart gets oxygen from the alveoli. The carbon dioxide in the blood goes into the alveoli at the same time.
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2 years ago
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Soon after the island of Hawaii rose above the sea surface (somewhat less than 1 million years ago), the evolution of life on th
krek1111 [17]

Answer:

The correct answer is- founder effect  

Explanation:

Founder effect occurs when a small number of individual isolates from the majority of the population by natural calamity or any other region. These isolated individuals show less genetic diversity than the larger population because they are less in numbers.  

Therefore founder effect makes a small group of individuals isolate from a bigger population and make them occupy a different habitat. So a founder population can go on a newly developed island and start reproducing there.

A founder population over time converts into a new species because of reproductive isolation from the main population.  So the evolution of life on the island of Hawaii should have been most strongly influenced by founder effect.

3 0
2 years ago
The membranes of both b cells and the cancer cells are largely composed of phospholipids. Explain how
iragen [17]
<h2>Answer:</h2><h2>when the membranes are fused, the polar parts of the phospholipids from one cell will interact with the phospholipids from the other cell .</h2>

Explanation:

Cell membrane is composed of phospholipid bilayer . Cell membrane is hydrophilic at the surface of outside of the cell and inside surface of the cell thus both surface of cell membrane is a hydrophilic . Interiorly cell membrane is hydrophobic or nonpolar region because membrane composed of long fatty acid chain interiorly . Inner surface of cell membrane have no contact with water or polar molecules . When membrane binds to each other then the polar parts of the phospholipids from one cell will interact with the phospholipids from the other cell , while nonpolar parts of cell avoid water and create bilayer phospholipid where hydrophobic tails are in between the hydrophilic heads .

 

5 0
2 years ago
Genetic linkage mapping for a large number of families identifies 4% recombination between the genes for Rh blood type and ellip
Cloud [144]

Answer:

0.2404

Explanation:

The genes R/r and E/e are linked and there is 4% recombination between them.

<u>The possible genotypes and phenotypes are:</u>

  • RR or Rr: Rh+ blood type
  • rr: Rh- blood type
  • EE or Ee: elliptocytosis
  • ee: normal red blood cells

Tom and Terri each have elliptocytosis (they are E_), and each is Rh+ (they are R_).

Tom's mother has elliptocytosis (E_) and is Rh- (rr), so she has the genotype Er/_r. His father is healthy (ee) and has Rh+ (R_), so he has the genotype eR/e_. Tom must have inherited his E allele from his mother and his R allele  from his father, so he has the genotype eR/Er.

Terri's father is Rh+ (R_) and has elliptocytosis (E_), while Terri's mother is Rh- (rr) and is healthy (ee) with the genotype er/er. Terry could only receive the chromosome <em>er </em>from her mother, and because she is heterozygous for both genes the dominant alleles were both received from her father. Terri's genotype is ER/er.

The frequency of recombination is 4%, so 4% of the produced gametes will be recombinant. There are two possible recombinant gametes, so each will appear 2% of the times (a frequency of 0.02).

<u />

<u>Tom will produce the following gametes:</u>

  • eR, parental (0.48)
  • Er, parental (0.48)
  • er, recombinant (0.02)
  • ER (recombinant (0.02)

<u>Terri will produce the following gametes:</u>

  • ER, parental (0.48)
  • er, parental (0.48)
  • Er, recombinant (0.02)
  • eR, recombinant (0.02)

A child Rh- with elliptocytosis has the genotype rrE_. This can happen from the independent combination of the following gametes from Tom and Terri respectively:

  • Er (0.48) × er (0.48) = 0.2304 Er/er
  • Er (0.48) × Er (0.02) = 0.0096 Er/Er
  • er (0.02) × Er (0.02) = 0.0004 er/Er

And the total probability of having a rrE_ child will be 0.2304 + 0.0096 + 0.0004 = 0.2404

6 0
2 years ago
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