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harina [27]
2 years ago
12

An automobile dealer can sell 12 cars per day at a price of $13,000. He estimates that for each $300 price reduction he can sell

two more cars per day. If each car costs him $10,000, and fixed costs are $1000, what price should he charge to maximize his profit? [Hint: Let x = the number of $300 price reductions.]
Mathematics
1 answer:
Blababa [14]2 years ago
5 0

Answer:

$ 1100

Step-by-step explanation:

Let p(x) be the price he charges for a car after x price reductions.

Since car costs him $10,000, and fixed costs are $1000

p(x) = 13000-10000-1000-300x = 2000 - 300x

Let  q(x) = 12 + 2x the quantity of cars sold after x price reductions.

and the profit he can make are given by:

Profit = R(x) = (12+2x)(13,000 - 10,000 - 1,000 - 300x) dollars.

As you can see, maximizing profit , we have to check where P'(x) = 0

And P''(x)<0.

So we get x = 3.

Replacing the value we get we get 2000 - 300 X 3 = 2000 - 900

                                                                  = $ 1100

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1 year ago
The price of a game that’s been discounted 18% OFF ITS list price (x)
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Find the center, vertices, and foci for the ellipse 25x^2 + 64y^2 = 1600
Alisiya [41]

Answer:

The answer to your question is below

Step-by-step explanation:

Data

Equation               25x² + 64y² = 1600

Process

1.- Divide all the equation by 1600

                             25x²/1600 + 64y²/ 1600 = 1600/1600

-Simplify

                              x²/64 + y²/ 25 = 1

2.- Equation of a horizontal ellipse

                             \frac{x^{2} }{a^{2}} + \frac{y^{2}}{b^{2}} = 1

3.- Find a, b and c

    a² = 64             a = 8

    b² = 25             b = 5

-Calculate c with the Pythagorean theorem

                   a² = b² + c²

-Solve for c

                   c² = a² - b²

-Substitution

                   c² = 8² - 5²

-Simplification

                  c² = 64 - 25

                  c² = 39

-Result

                  c = √13

4.- Find the center

          C = (0, 0)

5.- Find the vertices

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6.- Find the foci

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Jeremy opens a chocolate shop in the city. He pays $1,500 a month for rent and maintenance of the shop. The price of raw materia
KATRIN_1 [288]
Amount of money paid by Jeremy as rent and maintenance of shop per month = $1500
Cost of raw materials and manufacturing per month = $6000
Total cost that Jeremy has to spend per month = (1500 + 6000) dollars
                                                                            = 7500 dollars
Number of individual chocolates sold = 2400
Number of chocolates sold in boxes = 50 boxes
                                                           = (12 * 50) chocolates
                                                           = 600 chocolates
Then
Total number of chocolates sold by Jeremy = 2400 + 600
                                                                       = 3000
Now
Price of each chocolate = 7500/3000 dollars
                                       = 75/30 dollars
                                       = 5/2 dollars
                                       = 2.5 dollars
Price of 600 chocolates = 600 * (5/2) dollars
                                       = 300 * 5 dollars
                                       = 1500 dollars
Price of 12 chocolates = (1500/600) * 12
                                     = 15 * 2
                                     = 30 dollars
Then
We can say that each box of chocolate should be sold at $30. All the loose chocolates should be sold at $2.5 each.
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