Answer:
The total blood given is 5.5 liters
Thus, total alcohol needed for BAC (blood alcohol content) to exceed 0.1 gram per 100 ml will be 0.1/100 × 5500 = 5.5 grams alcohol.
1 oz = 28.3 grams
28.3 gram water = 28.3 ml
It has 20 percent alcohol by volume,
Therefore, alcohol in one drink will be:
20/100 × 28.3
= 5.66 ml
= 5.66 × 0.79 (density of ethanol)
= 4.47 gram
Thus, no of drinks will be 5.5 g / 4.47 g = 1.2
Hence, 1.2 drinks will make the BAC to exceed 0.1 g / 100 ml in the blood.
Answer:
Explanation:
check the attached files below for answer
E.the number of amino acids in the protein
<u>Answer:</u>
"Rainwater pouring from an eroded bank into a river" is a non-point source of water pollution.
<u>Explanation:</u>
Bank erosion is the washing away of stream or river banks. This is distinct from erosion of the watercourse bed, known as scour. These erosion undermines the roots of trees which develop by a lake. As the roots closely connect the soil, they form abutments that jut out above the surface.
Non-point source water contamination is induced by widespread and isolated waste sources such as rain and snowmelt runoff, spills, leaks, and sediment erosions. To release any pollutant, without a permit, from a point source into navigable waters is illegal according to the Clean Water Act.