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Julli [10]
2 years ago
11

At your​ school, 20​% of the class are marketing majors. You are randomly assigned to two partners in your statistics class. ​a)

What is the probability that the first partner will be a marketing​ major? ​b) What is the probability that the first partner​ won't be a marketing​ major? ​c) What is the probability that both will be marketing​ majors? ​d) What is the probability that at least one will be a marketing​ major?
Mathematics
1 answer:
Digiron [165]2 years ago
5 0

Answer:

a) 20%

b) 80%

c) There is 4% probability that both will be marketing majors.

d) There is a 36% probability that at least one will be a marketing​ major.

Step-by-step explanation:

At your​ school, 20​% of the class are marketing majors.

This means that for each student, there is a 20% that he is a marketing major and an 80% chance that he is not a marketing major.

a) What is the probability that the first partner will be a marketing​ major?

The probabilities for each student are independent, so it is 20%.

​b) What is the probability that the first partner​ won't be a marketing​ major?

80%

c) What is the probability that both will be marketing​ majors?

For each one, it is 20%. So:

P = 0.2*0.2 = 0.04

There is 4% probability that both will be marketing majors.

​d) What is the probability that at least one will be a marketing​ major?

That is one of them or both. For both, we found in c) that it is 4%.

For one of them, there are two cases. Either the first partner is and the second is not, or the other way. So, the probability that at least one will be a marketing major is

P = 0.04 + 2*0.2*0.8 = 0.36

There is a 36% probability that at least one will be a marketing​ major.

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Answer:

A. 4.26 in^2

Step-by-step explanation:

Step 1: Find the area of the sector DBC. Here we have to use the formula.

Area of a sector = Central Angle/360 *πr^{2}

The area of the sector DBC = (54/360)*3.14*8^{2}

= 30.16

Step 2: Area of segment CFD = Area of the sector DBC - Area of the ΔCBD

= 30.17 - 25.9

Area of segment CFD = 4.27in^2

8 0
2 years ago
True or​ false: when comparing two​ populations, the larger the standard​ deviation, the more dispersion the distribution​ has,
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2 years ago
Expressed as a percentage, how many more avocados does the city of
mash [69]

Answer:

In Phoenix they consume 60% more avocados than in Denver.

Step-by-step explanation:

Given that in Denver they consume 75 units of avocados, while in Phoenix they consume 120 units of said fruit, to determine the percentage difference between the consumption of both cities it is necessary to perform the following calculation:

75 = 100

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((120 x 100) / 75) = X

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Therefore, in Phoenix they consume 60% more avocados than in Denver.

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2 years ago
A bin of 5 transistors is known to contain 2 that are defective. The transistors are to be tested, one at a time, until the defe
xxMikexx [17]

Answer:

P(N_1 = a , N_2 = b)= \frac{1}{5-a C 1} * \frac{5-a C 1}{5C2} = \frac{1}{5C2}=\frac{1}{10}

Step-by-step explanation:

For the random variable N_1 we define the possible values for this variable on this case [1,2,3,4,5] . We know that we have 2 defective transistors so then we have 5C2 (where C means combinatory) ways to select or permute the transistors in order to detect the first defective:

5C2 = \frac{5!}{2! (5-2)!}= \frac{5*4*3!}{2! 3!}= \frac{5*4}{2*1}=10

We want the first detective transistor on the ath place, so then the first a-1 places are non defective transistors, so then we can define the probability for the random variable N_1 like this:

P(N_1 = a) = \frac{5-a C 1}{5C2}

For the distribution of N_2 we need to take in count that we are finding a conditional distribution. N_2 given N_1 =a, for this case we see that N_2 \in [1,2,...,5-a], so then exist 5-a C 1 ways to reorder the remaining transistors. And if we want b additional steps to obtain a second defective transistor we have the following probability defined:

P(N_2 =b | N_1 = a) = \frac{1}{5-a C 1}

And if we want to find the joint probability we just need to do this:

P(N_1 = a , N_2 = b) = P(N_2 = b | N_1 = a) P(N_1 =a)

And if we multiply the probabilities founded we got:

P(N_1 = a , N_2 = b)= \frac{1}{5-a C 1} * \frac{5-a C 1}{5C2} = \frac{1}{5C2}=\frac{1}{10}

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Prescription for Marilyn Jones
Vanyuwa [196]

Answer:

32  

Step-by-step explanation:

We can ignore Piroxicam, because it comes in capsules.

1. Number of Glucotrol tablets

Marilyn takes one tablet per day.

\text{No. of tablets} = \text{8 da} \times \dfrac{\text{1 tab}}{\text{1 da}} = \text{8 tab}

2. Number of Isoniazid tablets

Marilyn takes three tablets per day.

\text{No. tablets} = \text{8 da} \times \dfrac{\text{3 tab}}{\text{1 da}} =\text{24 tab}

3. Total tablets

Total tablets = 8 tab + 24 tab = 32 tab

Marilyn takes 32 tablets in eight days.

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