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2 years ago

Factor the expression given below. Write each factor as a polynomial in

Mathematics

1 answer:

kherson [118]2 years ago

6 0

The factorization of the expression of 43x³ + 216y³ is

(7x + 6y)(49x² - 42xy + 36y²)

Step-by-step explanation:

The sum of two cubes has two factors:

1. The first factor is $\sqrt[3]{1st}$ + $\sqrt[3]{2nd}$

2. The second factor is ( $\sqrt[3]{1st}$ )² - ( $\sqrt[3]{1st}$ ) ( $\sqrt[3]{2nd}$ ) + ( $\sqrt[3]{2nd}$ )²

Ex: The expression a³ + b³ is the sum of 2 cubes

The factorization of a³ + b³ is (a + b)(a² - ab + b²)

∵ The expression is 343x³ + 216y³

∵ $\sqrt[3]{343x^{3}}$ = 7x

∵ $\sqrt[3]{216y^{3}}$ = 6y

∴ The first factor is (7x + 6y)

∵ (7x)² = 49x²

∵ (7x)(6y) = 42xy

∵ (6y)² = 36y²

∴ The second factor is (49x² - 42xy + 36y²)

∴ The factorization of 43x³ + 216y³ is (7x + 6y)(49x² - 42xy + 36y²)

The factorization of the expression of 43x³ + 216y³ is

(7x + 6y)(49x² - 42xy + 36y²)

Learn more:

You can learn more about factors in brainly.com/question/10771256

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Answer:

8% or 0.08

Step-by-step explanation:

Probability of missing the first pass = 40% = 0.40

Probability of missing the second pass = 20% = 0.20

We have to find the probability that he misses both the passes. Since the two passes are independent of each other, the probability that he misses two passes will be:

Probability of missing 1st pass x Probability of missing 2nd pass

i.e.

Probability of missing two passes in a row = 0.40 x 0.20 = 0.08 = 8%

Thus, there is 8% probability that he misses two passes in a row.

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2 years ago

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The answer is c because is a vrtical line

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2 years ago

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Evaluate \dfrac14c+3d

Crank

Answer: $\frac{45}{2}$

Step-by-step explanation:

<h3> The exercise is: " Evaluate $\frac{1}{4}c + 3d$ when $c = 6$ and $d = 7$ </h3>

Given the following expression:

$\frac{1}{4}c + 3d$

You can follow these steps in order to evaluate it:

1. Substitute $c = 6$ and $d = 7$ into the expression provided in the exercise:

$\frac{1}{4}(6) + 3(7)$

2. Solve the multiplications. Remember that:

$\frac{a}{b}*\frac{c}{d}=\frac{ac}{bd}$

Then:

$=\frac{6}{4} +21$

3. Reduce the fraction. Notice that the numerator 6 and the denomiantor 4 can be both divided by 2. Then:

$=\frac{3}{2} +21$

4. Solve the addition:

$=\frac{3}{2} +\frac{21}{1}$

Since the number 21 has a denominator 1, the Least Common Denominator is:

$LCD=2$

Then, the sum is:

$=\frac{3+42}{2}=\frac{45}{2}$

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The Ignorance Survey: United Kingdom A survey was conducted in the United Kingdom, where respondents were asked if they had a un

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Answer:

Here we have given two catogaries as degree holder and non degree holder.

So here we have to test the hypothesis that,

H0 : p1 = p2 Vs H1 : p1 not= p2

where p1 is population proportion of degree holder.

p2 is population proportion of non degree holder.

Assume alpha = level of significance = 5% = 0.05

The test is two tailed.

Here test statistic follows standard normal distribution.

The test statistic is,

Z = (p1^ - p2^) / SE

where SE = sqrt[(p^*q^)/n1 + (p^*q^)/n2]

p1^ = x1/n1

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This we can done in TI_83 calculator.

steps :

STAT --> TESTS --> 6:2-PropZTest --> ENTER --> Input all the values --> select alternative "not= P2" --> ENTER --> Calculate --> ENTER

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Conclusion : There is not sufficient evidence to say that the percent of correct answers is significantly different between degree holders and non-degree holders.

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Answer:

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Step-by-step explanation:

Notation

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