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I am Lyosha [343]
2 years ago
10

A movie theater is filled to its capacity of 350. The theater charges $4.50 for children, $7.50 for students, and $12.50 for adu

lts. There are half as many adults as there are students. If the total ticket sales was $2415, how many children, students, and adults attended. Write your answer as an ordered triple in the form (# of children, # of students, # of adults). For example, (1,2,3).
Mathematics
2 answers:
Leno4ka [110]2 years ago
4 0

Answer:

<h2>(170;120;60).</h2>

Step-by-step explanation:

<h3>We know that:</h3>

Capacity of the theater: 350 people.

Adults is half the students.

Children's cost: $4.50

Student's cost: $7.50

Adults' cost: $12.50

Total Sales: $2415

We are gonna call <em>x </em>the children, <em>y </em>the students and <em>z </em>the adults:

So, the equation to express the capacity of the theater would be:

x+y+z=350

But, z=\frac{y}{2} (adults are have students)

So, the expression would be: x+y+\frac{y}{2} =350

<h3>Solving <em>y's </em>and Isolating <em>x </em>: </h3>

x+\frac{3y}{2} =350\\x=350-\frac{3y}{2}

<h3>Now, we need a expression for costs. We have:</h3>

4.50x+7.50y+12.50z=2415

<h3>Replacing the <em>x </em>and <em>z </em>equation:</h3>

4.50(350-\frac{3y}{2} )+7.50y+12.50\frac{y}{2}=2415

<h3>Now, we solve for <em>y</em>:</h3>

1575-6.75y+7.50y+6.25y=2415\\07y=2415-1575\\7y=840\\y=\frac{840}{7} =120

<h3>But, we know that adults are half as many students, so:</h3>

z=\frac{y}{2}=\frac{120}{2} =60

<h3>Lastly,</h3>

x+y+z=350\\x+120+60=350\\x=350-120-60\\x=170

<em>Therefore, there are 170 children, 120 students and 60 adults. Expressing the results as an ordered triple would be (170;120;60)</em>

7nadin3 [17]2 years ago
3 0

Answer:

Step-by-step explanation:

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Answer:

$60 per ticket

Step-by-step explanation:

$215 is what it costs after the discount, so add the amount taken off, back on.

215+25

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Then, divide by 4 to find the cost of each individual ticket.

240/4

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Hope it helps!

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Assume that x and y are both differentiable functions of t and find the required values of dy/dt and dx/dt. x2 + y2 = 25 (a) Fin
Artemon [7]

Answer:

(a) \frac{dy}{dt}=-3\frac{3}{4}

(b) \frac{dx}{dt}=3\frac{3}{4}

Step-by-step explanation:

x^{2} +y^{2}=25

Take \frac{d}{dt} of of each term.

\frac{d}{dt}(x^{2})+\frac{d}{dt}(y^{2})=\frac{d}{dt}(25)\\\\(\frac{d}{dx}(x^{2})*\frac{dx}{dt}) +(\frac{d}{dy}(y^{2})*\frac{dy}{dt})=\frac{d}{dt}(25)\\\\2x\frac{dx}{dt} +2y\frac{dy}{dt} = 0\\\\

For Question a

2y\frac{dy}{dt}=-2x\frac{dx}{dt}\\\\\frac{dy}{dt}=\frac{-2x\frac{dx}{dt}}{2y} \\\\\frac{dy}{dt}=-\frac{x}{y}\frac{dx}{dt}

Given that x = 3, y = 4, and dx/dt = 5.

\frac{dy}{dt}=-\frac{3}{4}*5=-\frac{15}{4}\\   \\\frac{dy}{dt}=-3\frac{3}{4}

For Question b

2x\frac{dx}{dt}=-2y\frac{dy}{dt}\\\\\frac{dx}{dt}=\frac{-2y\frac{dy}{dt}}{2x} \\\\\frac{dx}{dt}=-\frac{y}{x}\frac{dy}{dt}

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5 0
2 years ago
One way to measure whether the trees in the Wade Tract are uniformly distributed is to examine the average location in the north
tatyana61 [14]

Answer:

Null hypothesis be H₀ : μ = 100

Alternative hypothesis Hₐ : μ < 100

There is sufficient statistical evidence to suggest that the average location of Wade Tract is 100

Step-by-step explanation:

Here we have;

Let our null hypothesis be H₀ : μ = 100 Average location of trees in the Wade Tract is 100

Our alternative hypothesis becomes Hₐ : μ < 100 at 95% confidence level

Proposed average location in Wade Tract, μ = 100

Sample mean, \bar x = 99.74

Standard deviation, s = 58

Sample size, n = 584

The t test formula is therefore;

t=\frac{\bar{x}-\mu }{\frac{s }{\sqrt{n}}}

Therefore, with df = 584 -1 = 583, and α = (1 - 0.95)/2 = 0.025

We have t_{\alpha /2} = -1.65

Plugging in the values into the t test formula, we have t = -0.108338, from which the p-value is given as p = 0.4569 which is much more than the value of α, therefore, we accept the null hypothesis as follows;

There is sufficient statistical evidence to suggest that the average location of Wade Tract = 100.

7 0
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