<h3>Correct answer choice is:</h3><h2>B. Populations increase and decrease in a regular predictable pattern.</h2><h3>Explanation:</h3>
A population cycle in biology is a process where populations increase and decrease over an anticipated duration of time. There are many classes where population figures have logically anticipated models of reform although the full incentives for population cycles are one of the significant unsolved environmental difficulties.
Answer:
The normal role of this control element can be that of a negative modulator or regulator
Explanation:
For example, the lactose operon in the bacteria <em>Escherichia coli</em> is negatively regulated. In lactose absence a represor protein is produced, which inserts in the DNA operator site blocking transcription of structural genes. if for example a mutation affects the synthesis of this repressor, expression of structural genes will increase with no regulation.
A mutation in the DNA operator site that avoids insertion of the repressor, too.
A mutation in the gene that codes for the repressor, will also do the job
The term myoparesis is used to describe the weakness or slight paralysis of the muscles. The myoparesis can begin in a person suddenly or it might progress with gradual weakness of the muscles. The affected individual may suffer from weakness of the muscles with incomplete paralysis along with experiencing pain and spasms in the affected muscles. The causes for the development of myoparesis includes stroke, cerebral palsy, multiple sclerosis, and spinal cord injury.
Hence, the answer is 'weakness or slight muscular paralysis'.
I’d say B is the best choice
Hope this helps
-AaronWiseIsBae
Answer:
p = 0.34
Explanation:
The green allele is recessive, meaning two copies of q (qq) are required to be green. Conversely, animals that are either pp or pq will be blue.
If 44 organisms are green, that means 44 are qq.
For genotype frequencies, the equation is:
homozygous dominant genotype + heterozygous + homozygous recessive = 100%
Which is denoted as
p² + 2pq + q² = 1
We know that q² = 44/100 = 0.44
To work out q, we can do 
= 0.66
For allele frequencies, the total must add up to 100%, so
p + q =1
We know that q= 0.66
So p = 0.34, because 0.66 + 0.34 = 1
