F Enzyme Action and Changes<span> in pH. G The Effect of Temperature on Enzyme Populations. H How Enzyme Action Alters Temperature. J. The Effect of Temperature on Enzyme Action. 11 </span>Two parent butterflies<span> with </span>normal wings have offspring<span> with </span>altered wing shapes<span>. What </span>most likely caused<span> this</span>change<span>? A speciation.
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Answer:
The hook spurs allow it to be carried my fur because the hooked spurs can connect to the fur and be dropped at a new place, were a new generation of plants can grow! :D your welcome!
Explanation:
Answer:
True
Explanation:
Oogenesis includes the formation of one egg cell from a single oocyte or egg mother cell. The diploid primary oocytes in the ovaries enter into the first meiotic division and form a haploid secondary oocyte and a haploid first polar body. After fertilization, the secondary oocytes complete the meiosis-II and forms one large ovum and a second polar body. The ovum formed by meiosis-II is much larger than the second polar body due to the unequal distribution of cytoplasm during meiosis-II. This imparts enough amount of cytoplasm in the zygote to support the mitosis without any cell growth.
Answer:
See the answer below
Explanation:
Let the disorder be represented by the allele a.
Since the disease is an autosomal recessive one, affected individuals will have the genotype aa and normal individuals will have the genotype Aa or AA.
Since the four adults are carriers, their genotypes would be Aa.
Aa x Aa
Progeny: AA 2Aa aa
Probability of being affected = 1/4
Probability of being a carrier = 1/2
Probability of not being affected = 3/4
(a) The chance that the child second child of Mary and Frank will have alkaptonuria = 1/2
(b) The chance that the third child of Sara and James will be free of the condition = 3/4
(c)
(d) If someone has no family history of the disorder, their genotype would be AA.
AA x aa
4 Aa
<em>The chance that a child with alkaptonuria will have an offspring with alkaptonuria if the child's mate has no family history </em>= 0
(e)
(f) <em>The chance that a child with alkaptonuria will have an offspring with alkaptonuria if the child's mate has no family history</em> = 0
Answer:
gene encoding enzymes for glycolysis.
Explanation:
Plasmid may be defined as an extra chromosomal circular DNA that replicate independently of the main chromosomal material. Plasmid are generally used for the manipulation of genes in molecular technologies.
Plasmid can encode gene for toxins, antibacterial resistance and for the unusual substrate degradation. The plasmid cannot code enzyme for glycolysis because these enzymes are already present in the host organisms. Glycolysis enzymes are independent on the plasmid regulation.
Thus, the correct answer is option (3).
