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iris [78.8K]
2 years ago
4

Birth weights of full-term babies in a certain area are normally distributed with mean 7.13 pounds and standard deviation 1.29 p

ounds. A newborn weighing 5.5 pounds or less is a low-weight baby. What is the probability that a randomly selected newborn is low-weight? Do not round, and do not convert the probability as a percentage.
Mathematics
1 answer:
Roman55 [17]2 years ago
8 0

Answer:

Step-by-step explanation:

Birth weights of full term babies are normally distributed with mean 7.13 pounds and standard deviation 1.29 pounds. Using normal distribution,

z = (x - μ) /σ

Where μ = mean

σ = standard deviation.

x = Birth weights of full term babies

From the information given,

μ = 7.13

σ = 1.29

x = 5.5

the probability that a randomly selected newborn is low-weight means that the newborn is weighing 5.5 pounds or less.

For P(x lesser than or equal to 55) ,

Z= (5.5-7.13)/1.29 = -1.63 /1.29 = -1.263

From the normal distribution table, the value of z = -1.263 = 0.1038

P(x lesser than or equal to 55) = 0.104

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An unloaded truck and trailer, with the driver aboard, weighs 30{,}00030,00030, comma, 000 pounds. When fully loaded, the truck
kari74 [83]

Answer:

1131 pounds.

Step-by-step explanation:

We have been given that an unloaded truck and trailer, with the driver aboard, weighs 30,000 pounds. When fully loaded, the truck holds 26 pallets of cargo, and each of the 18 tires of the fully loaded semi-truck bears approximately 3,300 pounds.

First of all, we will find weight of 18 tires by multiplying 18 by 3,300 as:

\text{Weight of tires of the fully loaded semi-truck}=18\times 3,300

\text{Weight of tires of the fully loaded semi-truck}=59,400

The weight of 26 pallets would be weight of 18 tires minus weight of unloaded truck.

\text{Weight of 26 pallets of cargo}=59,400-30,000

\text{Weight of 26 pallets of cargo}=29,400

Now, we will divide 29,400 by 26 to find average weight of one pallet of cargo.

\text{Average weight of one pallet of cargo}=\frac{29,400}{26}

\text{Average weight of one pallet of cargo}=1130.769230769

\text{Average weight of one pallet of cargo}\approx 1131

Therefore, the average weight of one pallet of cargo is approximately 1131 pounds.

3 0
2 years ago
Jessica was sitting in row 9, seat 3 at a soccer game when she discovered her ticket was for row 1, seat 1. Write a rule to desc
Westkost [7]

rule is to  shift 8 units left & , shift 2 units down , Correct option C)  T<-8,-2> (Jessica) ,

<u>Step-by-step explanation:</u>

Here we have , Jessica was sitting in row 9, seat 3 at a soccer game when she discovered her ticket was for row 1, seat 1. We need to Write a rule to describe the translation needed to put her in the proper seat. Let's do this:

Suppose the above problem in coordinate system where we have a point P(9,3) , And we need to write rule for translation of this point to Q(1,1) .

Let , (x,y)=(9,3) , Now shift 8 units left i.e.

⇒  (x,y)=(9,3)

⇒  (x-8,y)=(9-8,3)

⇒  (x-8,y)=(1,3)

Now , shift 2 units down i.e.

⇒  (x-8,y)=(1,3)

⇒  (x-8,y-2)=(1,3-2)

⇒  (x-8,y-2)=(1,1)

Therefore , rule is to  shift 8 units left & , shift 2 units down , Correct option C)  T<-8,-2> (Jessica) ,

4 0
2 years ago
Chloe made a conjecture that given any two numbers, the greater number can always be arranged into more arrays.
Anna11 [10]

Solution:

Array means arrangement of numbers in terms of rows and columns.

The conjecture is not True.

So, the conjecture made by chloe that given any two numbers, the greater number can always be arranged into more arrays is not true.

For example ,

1.(2,3)

2→(2×1),(1×2)

3→(3×1),(1×3)

This pair has same number of arrays because both of them are prime.

2. (3,4)

Here, 4>3

3→ (3 × 1),(1×3)

4→(4×1),(1×4),(2×2)

The pair of numbers are Co-prime, one of them is not prime. So Composite number has more number of arrays.

4. (6,11)

6→(1×6),(6×1),(2×3),(3×2)

11→(1×11),(11×1)

The number 6 is smaller, but it has more number of arrays.

5. (6,8)

6→(1×6),(6×1),(2×3),(3×2)

9→(1×9),(9×1),(3×3)

Both the numbers are composite.Smaller number 6 has more arrays.

These examples disprove the Conjecture made by Chloe, which states that given any two numbers, the greater number can always be arranged into more arrays.



4 0
2 years ago
Claire power walks 1/9 of a mile in 1/54 of an hour compute the unit rate as the complex fraction
Phantasy [73]
1/9 * 54/1 = 54/9.

So she is walking 6mph.
4 0
2 years ago
Read 2 more answers
A environmental initiative has the goal of saving at least 25 2525 million hectares of rainforest through both planting trees an
Anestetic [448]

Answer:

The possible way for the initiative to accomplish its goal without exceeding its budget is use 12.5 hectares for planting trees and 12.5 hectares by purchasing land.

Step-by-step explanation:

Let the variable <em>X</em> represent the amount of land used for planting trees and <em>Y</em> represent the amount of land purchased.

The goal of the environmental initiative is to save at least 25 million hectares of rain forest.

That is:

<em>X</em> + <em>Y</em> = 25....(i)

Now it is provided that:

  • The cost of planting trees is $ 400 per hectare.
  • The cost of purchasing land is $ 260 per hectare.
  • The initiative has a budget of $8,250 million.

Using the above data it can be said that:

400<em>X</em> + 260<em>Y</em> = 8250....(ii)

Solve equations (i) and (ii) simultaneously.

\ \ \ \ x+y=25]\times 260\\400x+260y=8250\\\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\\\\\Rightarrow\\\\260x+260y=6500\\400x+260y=8250\\(-)\_\_\_\_\_\ (-)\_\_\_\_(-)\_\_\_\\\\\Rightarrow\\\\-140x=-1750\\\\x=\frac{1750}{140}\\\\x=12.5

Then the value of <em>y</em> is:

x+y=25\\y=25-x\\y=25-12.5\\y=12.5

Thus, the possible way for the initiative to accomplish its goal without exceeding its budget is use 12.5 hectares for planting trees and 12.5 hectares for purchasing land.

4 0
2 years ago
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