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Ann [662]
2 years ago
13

Which DFS option can be used to help manage peak bändwidth needs by forcing replication to occur during off hours?

Computers and Technology
1 answer:
andrey2020 [161]2 years ago
5 0

Answer: D. Scheduling

Explanation:

Distributed file system (DFS) replication scheduling are used most especially when large files need to be replicated across lower bandwidth connections. It helps manage peak bandwidth by forcing replication to occur during off hours

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The __________ of a desktop computer is the case that houses the computerâs critical parts, such as the processing and storage d
Phantasy [73]
You said it in your question. The case! Though it's also given other names, such as housing, chassis, enclosure etc.
4 0
2 years ago
You resurrected an old worksheet. It appears to contain most of the information that you need, but not all of it. Which step sho
shtirl [24]

Answer:

a)

Explanation:

Since the worksheet contains most of the data that you need, there is a decent possibility that it also contains the data that you are missing. Therefore, you should check for data you have previously hidden. Sometimes, some data in a worksheet may become irrelevant in a given moment, and instead of deleting it since it may be useful later most people tend to make that data hidden. So checking for previously hidden data may be the best solution in this scenario.

7 0
1 year ago
Peter accumulated many photos from his visit to Wisconsin. He wants to upload these photos to a social networking site. Which fi
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Answer:

JPG / JPEG best choice and work well on websites

Explanation:

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Best choice for posting on social media channels

7 0
2 years ago
Write a program to input value of three sides, to check triangle is triangle is possible to form of not​
NeTakaya

Answer:

Explanation:

import java.util.Scanner;

public class KboatTriangleAngle

{

  public static void main(String args[]) {

      Scanner in = new Scanner(System.in);

      System.out.print("Enter first angle: ");

      int a1 = in.nextInt();

      System.out.print("Enter second angle: ");

      int a2 = in.nextInt();

      System.out.print("Enter third angle: ");

      int a3 = in.nextInt();

      int angleSum = a1 + a2 + a3;

       

      if (angleSum == 180 && a1 > 0 && a2 > 0 && a3 > 0) {

          if (a1 < 90 && a2 < 90 && a3 < 90) {

              System.out.println("Acute-angled Triangle");

          }

          else if (a1 == 90 || a2 == 90 || a3 == 90) {

              System.out.println("Right-angled Triangle");

          }

          else {

              System.out.println("Obtuse-angled Triangle");

          }

      }

      else {

          System.out.println("Triangle not possible");

      }

  }

}

OUTPUT:

3 0
2 years ago
Explain what all sensory receptors have in common.
sp2606 [1]
The correct answer is that all receptors are considered to have the same feature, which is being a transducer.

Transducers change vitality starting with one form then onto the next. Generally, the receptor cells don't create an activation impulse by themselves. Rather, they create a progressively expanding potential, which triggers enactment of the afferent nerve fiber to which they are associated.
7 0
2 years ago
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