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LUCKY_DIMON [66]
2 years ago
11

A network administrator has received the IPv6 prefix 2001:DB8::/48 for subnetting. Assuming the administrator does not subnet in

to the interface ID portion of the address space, how many subnets can the administrator create from the /48 prefix?
Computers and Technology
1 answer:
AveGali [126]2 years ago
6 0

Answer:

subnets=65536

Explanation:

As we know that,

-->interface ID portion of address starts from 64

--> we have 48 network prefix

so

available bits for subnet are = 64-48=  16

so with 16 bit address we can create subnet = 2^16 = 65535

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Answer:

The programming language is not stated; However, I'll answer your question using C++ programming language.

Comments are used for explanatory purpose

Program starts here

#include<iostream>

#include <string>

using namespace std;

int main()

{

//Declare Variables

string firstName, middleName, lastName;

char firstInitial, middleInitial, lastInitial;

/*Initialize firstName, middleName and lastName (Replace values with your details)*/

firstName = "First Name";

middleName = "Middle Name";

lastName = "Last Name";

 

// Get Initials

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//Print Results

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2 years ago
You are attempting to open a file containing a list of integer numbers, each on a separate line, and read them into Python as in
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Answer:

The answer to this question can be given as:

Statement:

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An array of ints, arr, has been declared and initialized. Write the statements needed to reverse the elements in the array. So,
Yuki888 [10]

Answer:

The sample output is below.

The code is attached.

Explanation:

Sample Output:

Original array is: 1 2 457 4 Reversed array is: 4754 2 1

Code to copy:

import java.io.*;

class Main

{

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    {

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         int temp;

         //Check if array is empty.

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         int count=0;

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         for(int i=0;i<arr.length;i++)

             count++;

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         for(int i=0; i<count;i++)

         {

             System.out.print(arr[i]+" ");

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         revArray(arr, 0, count-1);

         System.out.println("\nReversed array is:");

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11111nata11111 [884]

Answer:

See explaination

Explanation:

Code for detect_column_level_data_entry_errors.py:

# File: detect_column_level_data_entry_errors.py

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def main():

input_filename = input('Please enter the input filename: ')

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infile.close()

main()

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2 years ago
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