Passive readers expect an author to do all the work, to motivate them and keep them interested.
So, I believe the answer is D
Answer:
The answer is toy
Explanation:
I think toy is the odd one out
Statement to be written in cell B10 :
IF ( B9 >= 470000, 35000, 1000)
Formula:
IF ( logical_test , [value_if_true] , [value_if_false] )
Explanation:
- logical_test = Net Profit After Tax (cell B9)
- value_if_true = 35000
<em>(if the Net Profit After Tax (cell B9) is greater than or equal to 47000 )</em>
<em> </em>3<em>.</em> value_if_false = 1000
<em>(if the Net Profit After Tax (cell B9) is lesser than 47000 )</em>
Each value should be separated by comma.
Answer:
The third option is correct.
Explanation:
The following option is true because it's a derived with that Throwable class. More than that exception type, it is also other category called Error originating through that Throwable class. As any other class, the exception class will also include fields as well as functions. So, the following are the reason that describes the following answer is true according to the exception class.
The other options are not appropriate according to the following scenario.
Answer:
<u>The total time elapsed from the time a bit is created (from the original analog signal at Host A) until the bit is decoded (as part of the analog signal at Host B is </u><u>25.11 ms</u>
Explanation:
Host A first converts the analog signal to a digital 64kbps stream and then groups it into 56-byte packets. The time taken for this can be calculated as:
time taken 1= 
= (56 x 8) bits / 64 x 10³ bits/s
= 7 x 10⁻³s
time taken 1= 7 ms
The transmission rate of the packet from Host A to Host B is 4 Mbps. The time taken to transfer the packets can be calculated as:
time taken 2= (56 x 8) bits / 4 x 10⁶ bits/s
= 1.12 x 10⁻⁴ s
time taken 2= 112 μs
The propagation delay is 18 ms.
To calculate the total time elapsed, we need to add up all the time taken at each individual stage.
<u />
<u> = Time taken 1 + Time taken 2 + Propagation Delay</u>
= 7 ms + 112 μs + 18 ms
= 0.025112 s
= 25.11 ms