Question

B. Write a function that takes one double parameter, and returns a char. The parameter represents a grade, and the char represents the corresponding letter grade. If you pass in 90, the char returned will be ‘A’. If you pass in 58.67, the char returned will be an ‘F’ etc. Use the grading scheme on the syllabus for this course to decide what letter to return.

Answer 1

Answer:

#include <iostream>

#include <cstdlib>

using namespace std;

char grade(double marks){

   if(marks>=90)

   {

       return 'A';

   }

   else if (marks >=80 && marks<90)

   {

       return 'B';

   }

   

   else if (marks >=70 && marks<80)

   {

       return 'C';

   }

   

   else if (marks >=60 && marks<70)

   {

       return 'D';

   }

     else if ( marks<60)

   {

       return 'F';

   }

}

int main()

{

   double marks;

cout <<"Ener marks";

cin >>marks;

char grd=grade(marks);

cout<<"Grae is "<<grd;

return 0;

}

Explanation:

Take input from user for grades in double type variable. Write function grade that takes a parameter of type double as input. Inside grade function write if statements defining ranges for the grades. Which if statement s true for given marks it returns grade value.

In main declare a variable grd and store function returned value in it.