<span>The action of Helicase is to create replication forks and replication bubbles. Helicase is the first step in the DNA replication process. Helicase is an enzyme that breaks the hydrogen bond between the parental DNA to free the DNA double helix. The area where it unwinds is called as replication fork.</span>
Answer:
C) 19.7%
Explanation:
The new population distribution after climate change wiped out homozygous recessive dinosaurs is:
The percentage of offspring of this new population that are homozygous recessive is given by:
19.7% of these newborn dinosaurs died
Answer:
The options:
What would be the next step in this experiment?
A. construct a hypothesis and record data
B. make observations and draw a conclusion
C. ask questions and construct a hypothesis
D. analyze the results and make a conclusion
The ANSWER should be D
D. analyze the results and make a conclusion
Explanation:
It should be D, the hypothesis has been proposed by her and she's left with conclusion on the experiment. From the type of exleriment, she has little observations to make since there's is a remote conclusion in a set time period.
If you were to cross a large redwood tree, like for an example a sequoia, from the middle of the trunk you would first cross the annual rings, indicators of the trunk growth over the years, then after that you would cross the phloem, the ''piping'' of the tree responsible for the transport of water throughout the tree and in the end you would cross the tree's bark, the protective layer on surface of the trunk.
Answer:
Explanation:
To calculate the recombination frequency, we have to know that 1% of recombinations = 1 map unit = 1cm. And that the maximum recombination frequency is always 50%.
The map unit is the distance between the pair of genes for which every 100 meiotic products, one of them results in a recombinant one.
So, en the exposed example:
- J and K are autosomal genes
- J and K are separated by 60 M.U.
- 60 M.U. means that there is 60% of recombination.
Cross) J K / j k x j k / j k
Gametes) JK Parental jk, jk, jk, jk
jk Parental
Jk Recombinant
jK Recombinant
One map unit equals 1% of recombination frequency. This means that every 100 meiotic products, one of them is a recombinant one.
1 M.U. -------------- 1% recombination
60 M.U. ------------ 60% recombination
30% Jk + 30% jK
100 M.U. - 60 M.U. = 40 M.U.
40M.U.--------------40 % Parental (Not recombinant)
20% JK + 20% jk
Punnet Square) JK jk Jk jK
jk JK/jk jk/jk Jk/jk jK/jk
J K / j k = 20%
j k / j k = 20%
J k / j k = 30%
j K / j k = 30%
