He would be driving approximately 110 km an hour
Answer:
<h3>AC=96 units.</h3>
Step-by-step explanation:
We are given a parallelogram ABCD with diagonals AC and BD intersect at point E.
, and CE=6x .
<em>Note: The diagonals of a parallelogram intersects at mid-point.</em>
Therefore, AE = EC.
Plugging expressions for AE and EC, we get
Subtracting 6x from both sides, we get
Factoriong quadratic by product sum rule.
We need to find the factors of -16 that add upto -6.
-16 has factors -8 and +2 that add upto -6.
Therefore, factor of quadratic is (x-8)(x+2)=0
Setting each factor equal to 0 and solve for x.
x-8=0 => x=8
x+2=0 => x=-2.
We can't take x=-2 as it's a negative number.
Therefore, plugging x=8 in EC =6x, we get
EC = 6(8) = 48.
<h3>AC = AE + EC = 48+48 =96 units.</h3>
An isosceles triangle is a special type of triangle that has two equal sides. Consequently, the two base angles are also equal. Since the interior angles of a triangle should sum up to 180°, the general equation should be
180° = 2*Base angle + Vertex angle
Let the base angle be x. Thus, the vertex angle is equal to
Vertex angle = 4x - 6
Substituting,
180 = 2x + 4x - 6
x = 31°
Vertex angle = 4(31°) - 6
Vertex angle = 118°
First of all, lets consider that you made a litte mistake and you meant this problem.........
<span>"The combined average weight of an okapi and a llama is 450 kilograms. The average weight of 3 llamas is 190 kilograms more than the average weight of one okapi. On average, how much does an okapi weigh, and how much does a llama weigh?"
This is a system of two equations.
Let it be X the average weight of a LLAMA
And Y the average weight of an OKAPI
X + Y = 450 kg 1)
3X = 190 kg +Y 2)
So, with 1) we have that Y = 450 - X
We subsitute in 2) and we have
3X = 190 + (450 -X).............We solve for X ....==> 4X = 640kg ==> X = 160kg
..We replace X in 1 and get => Y = 450kg -X = 450kg -160kg = 290kg
</span>160kg....... average weight of a LLAMA
290kg........average weight of an OKAPI
