Answer:
A and B are the answers.
Explanation:
Believe me I took a test a while ago with this question
Answer:
UCS: sticks part of the toy into the electrical outlet
UCR: frightened and crying
CS: toy
CR: frightened to toy
Explanation:
Classical conditioning is a form of learning whereby a conditioned stimulus becomes associated with an unrelated unconditioned stimulus, in order to produce a behavioral response known as a conditioned response.
<u>Unconditioned stimulus</u> (UCS) is an agent that leads to a response without training. In this example, the child won't know that he can have electrical shock playing with toys.
<u>Unconditioned response</u> (UCR) is an automatic response to a UCS that's why the child starts crying and frightened.
<u>Conditioned stimulus</u> (CS) is a former natural stimulus that comes to elicit a given response after pairing with a UCS. In this situation, CS is when mom gives the same toys to the baby that was the reason for electrical shock.
<u>Conditioned response</u> (CR) is a learned response to a CS because the baby shows fear when he saw the same toys. It is his learned behavior.
Before a cell goes through cell division (mitosis), it must grow and make a copy of its DNA which is termed as an Inter-phase.
<u>Explanation:</u>
Some tasks must be carried out by the cells before they undergo division: The cell must grow, it must copy the genetic material (DNA) present in it, and divide into two daughter cells. These steps carried out by cells are termed as cell cycle.
Cells that contains a nucleus or Eukaryota cells, there are two major phases called interphase and the mitotic (M) phase. that comprises the cell cycle.
In inter-phase, growth of the cell and making a copy of its DNA is carried out.
In mitotic (M) phase, the cell separation of the DNA in the cell into two sets and division of its cytoplasm takes place resulting in the formation of two new cells.
Answer:
D. 0.60
Explanation:
If the population is in Hardy-Weinberg equilibrium, the genotypic frequencies are:
- freq AA = p²
- freq Aa = 2pq
- freq aa = q²
<em>p</em> is the frequency of the Rh positive allele (A) and <em>q</em> is the frequency of the Rh-negative allele (a).
If 84% of the population is Rh-positive, then 16% is Rh-negative and has the genotype <em>aa</em>. Therefore:
q² = 0.16
q = √0.16
q=0.4
And because p+q=1,
p = 1 - 0.4
p = 0.6
The frequency of the Rh-positive allele is 0.6
The answer is one (1) billion tons of phytoplankton at any one time. Annually, its recorded that there is approximately 45 billion tons of phytoplankton in the ocean. Other than being a source of food for fish, they are critical in the carb9n cycle. This phytoplankton incorporates 45–50 billion tons of inorganic carbon into their cells and are the largest source of atmospheric oxygen.
