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Pavlova-9 [17]
2 years ago
11

Three years ago, the U.S. dollar/euro exchange was 1.32 USD/EUR. Over the last three years, the price level in the United States

has increased by 18%, and the price level in the Eurozone has increased by 12%. If the current exchange rate is 1.40 USD/EUR, the real rate over the period has: A. increased, and Eurozone goods are now more expensive to U.S. customers. B. decrease, and Eurozone goods are now more expensive to U.S. customers. C. increases, and U.S. goods are now more expensive to Eurozone customers.
Business
1 answer:
jeyben [28]2 years ago
6 0

Answer:

A. increased, and Eurozone goods are now more expensive to U.S. customers

Explanation:

The exchange rate represents a link between domestic prices and foreign prices, so Three years ago, Price in the Eurozone was:

P1 (US)= 1.32 USD / EUR * P1 (Eurozone)

Now, after three years of inflation, the new prices are

P2 (US)= 1.18* P1 (US)

P2 (EUROZONE) = 1.12 *P1 (EUROZONE)

So, if we replace in the equation =

P2 (US)/1.18 = 1.32 * P2 ( EUROZONE)/1.12

P2 (US) = (1.32 * 1.18)/1.12 *P2 (EUROZONE)

P2 (US) = 1.39 P2 (EUROZONE)

As we can see, the teorical exchange rate should be 1.39 but we have a REAL exchange rate of 1.4, which is greater, the prices are now more expensive to US customers

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A mail-order house uses 18,000 boxes a year. Carrying costs are 60 cents per box a year, and ordering costs are $96. The followi
LuckyWell [14K]

Answer:

Explanation:

Given that:

A mail-order house uses 18,000 boxes a year.

Carrying costs are 60 cents per box a year =$0.60

and ordering costs are $96.

Determine:

A. The optimal order quantity.

The optimal order quantity can be calculated by using the formula:

Q_o = \sqrt{\dfrac{2DS}{H}}

Q_o = \sqrt{\dfrac{2*18000*96}{0.60}}

Q_o = \sqrt{\dfrac{3456000}{0.60}}

Q_o = \sqrt{5760000}

Q_o = 2400 \ boxes

B. The number of orders per year.

of boxes: 1,000-1,999 Price per box: $1.25

of boxes: 2,000- 4,999 Price per box: $1.20

of boxes: 5,000- 9,999 Price per box : $1.15

of boxes: 10,000 or more Price per box : $1.10

SInce 2400 boxes lies within ''of boxes: 2,000- 4,999 Price per box: $1.20 ''

Total cost = Carrying cost + ordering cost + Purchasing cost

Total \ cost =(\dfrac{Q}{2} )H +(\dfrac{D}{Q}) S+PD

Total \ cost =(\dfrac{2400}{2} )0.60 +(\dfrac{18000}{2400}) 96+1.20*18000

Total cost  = ( 1200) 0.60 + 7.5(96) + 1.20(18000)

Total cost  = 720 + 720 + 21600

Total cost  =  $ 23040

If the order size is 5000, the price per box will be 1.15

Total \ cost =(\dfrac{Q}{2} )H +(\dfrac{D}{Q}) S+PD

Total \ cost =(\dfrac{5000}{2} )0.60 +(\dfrac{18000}{5000}) 96+1.15*18000

Total cost = 2500 (0.60) + 3.6 (96) + 20700

Total cost = 1500 + 345.6 + 20700

Total cost = $22545.6

If the order size is 10000 , the price per box will be 1.10

Total \ cost =(\dfrac{Q}{2} )H +(\dfrac{D}{Q}) S+PD

Total \ cost =(\dfrac{10000}{2} )0.60 +(\dfrac{18000}{10000}) 96+1.10*18000

Total cost = 5000 (0.60) + 1.8(96)  + 19800

Total cost =  3000 + 172.8 + 19800

Total cost = $22972.8

From the three total cost, the least minimum cost of ordering is: 5000

So; the number of orders per year = total number of boxes per year/ boxes per order

the number of orders per year = 18000/5000

the number of orders per year = 3.6 orders per year

8 0
1 year ago
Part X requires machining on a milling machine (operations A and B are required).
Inga [223]

Answer:atleast 5 machines

Explanation:

Quantity required (Q) = 3000

Maintainace due = 500 parts

3000 / 500 = 5 = 6 Maintainace

Repair time = 6 × 30 minutes = 300 minutes = 5 hours.

operation time = 5 × 18 × 60 = 5400 minutes

Total operation time = Total operation hours - repair time

5400 - 300 = 5100 hours

For A:

(Standard time × Q) / (reliability × time efficiency × scrap × total working hours)

(3 × 3000) / (. 95×.95×5100)

9000/4602.75 = 1.96

For B:

(Standard time × Q) / (reliability × time efficiency × scrap × total working hours)

(5 × 3000) / (.95×.9×5100)

15000/4360.5 = 3.44

(1.96 + 3.44) = 166.56

=5. 4

5 0
2 years ago
Assume that you are on the financial staff of Vanderheiden Inc., and you have collected the following data: The yield on the com
finlep [7]

Answer:

Ke = D1/Po(1-F) + g

Ke = $0.65/17(1-0.1) + 0.06

Ke = 0.0425 + 0.06

ke = 0.1025 = 10.25%

WACC = Ke(E/V) + Kd(D/V)(1-T)

WACC = 10.25(55/100) + 7.75(45/100)(1-0.4)

WACC = 5.6375 + 2.0925

WACC = 7.73%

Explanation:

In this case, there is need to calculate cost of equity in the light of floatation cost using the above formula. Thus, we will now calculate WACC by considering cost of equity and the proportion of equity in the capital structure plus after-tax cost of debt and the proportion of debt in the capital structure.

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2 years ago
Rosa purchased three call option contracts on ABC stock with a strike price of $27 when the option premium was quoted at $1.1. T
IrinaK [193]

Answer:

Explanation:

Profit on a long call option = max(St - X, 0) - premium paid  

Profit on a long call option = max(29 - 27, 0) - 1.1

Profit on a long call option = max(2, 0) - 1.1

Profit on a long call option = 2 - 1.1

Profit on a long call option = 0.9 per share

Total profit on the long call option = 0.9 * 100 shares per contract * 3 contracts  = 0.9 * 100 * 3  = $270

Net profit on this investment = 270 - 10

Net profit on this investment = $260

8 0
2 years ago
Show Me How On February 22, Stewart Corporation acquired 12,000 shares of the 400,000 outstanding shares of Edwards Co. common s
Cerrena [4.2K]

Answer:

Explanation:

The journal entries are shown below:

1.  Investment in shares of Edwards Co A/c Dr $600,120

              To Cash A/c                                                              $600,120

(Being the purchase of stock is made)

The investment is computed below:

= Number of shares acquired × par value of common stock + commission charges

= 12,000 shares × $50 + $120

= $600,120

2. Cash A/c Dr $16,800

         To Dividend A/c $16,800

(Being dividend received is recorded)

The receipt of dividend is shown below:

=  Number of shares × cash dividend per share

= 12,000 shares × $1.40

= $16,800

3.  Cash A/c Dr $247,900

             To Profit on sale $47,860

             To Investment in shares of Edwards Co A/c $200,040

(Being sale of shares is recorded and the remaining amount is credited to the profit)

The computation of this above entry is shown below:

Cash Account = Number of shares sold  × par value of common stock - commission charges

= $4,000 × $62 - $100

= $247,900

Profit on sale = (Purchase of stock ÷  Number of shares acquired) × Number of shares sold

= ($600,120 ÷ 12,000) shares × 4,000 shares

= $200,040

8 0
2 years ago
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