Read the proof. Given: AEEC; BDDC Prove: △AEC ~ △BDC Statement Reason 1. AEEC;BDDC 1. given 2. ∠AEC is a rt. ∠; ∠BDC is a rt. ∠
2. definition of perpendicular 3. ∠AEC ≅ ∠BDC 3. all right angles are congruent 4. ? 4. reflexive property 5. △AEC ~ △BDC 5. AA similarity theorem What is the missing statement in step 4? ∠ACE ≅ ∠BCD ∠EAB ≅ ∠DBC ∠EAC ≅ ∠EAC ∠CBD ≅ ∠DBC
2 answers:
Answer:
C: ∠EAC ≅ ∠EAC
Step-by-step explanation:
BECAUSE ITS RIGHT
Answer:
The missing Statement is
4. ∠EAC ≅ ∠EAC 4. reflexive property
Step-by-step explanation:
Given:
AEEC; BDDC
To Prove:
△AEC ~ △BDC
Proof:
In △AEC and △BDC
Statement Reason
1. AE⊥EC;BD⊥DC 1. given
2. ∠AEC is a rt. ∠; ∠BDC is a rt. ∠ 2. definition of perpendicular
3. ∠AEC ≅ ∠BDC 3. all right angles are congruent
4. ∠EAC ≅ ∠EAC 4. reflexive property
5. △AEC ~ △BDC 5. AA similarity theorem
You might be interested in
Answer:
A (4-g)1.5
Step-by-step explanation:
hope this helps if you need a explanation just ask in the comments and I will.
There were 350 hamburgers sold on Saturday. Hope this helps!
Your answer is A. Megan is correct. When two lines have different slopes, they must intersect, producing one solution.
X/5 = 16
x = 80
80+10/ 6 = 90/6 = 15..
