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Ne4ueva [31]
2 years ago
13

A client is asking for a printing solution that will print three sheets of paper with identical information on each page with a

single pass of the printer. Furthermore, the client requests that the solution take the least amount of time and effort to maintain. Which of the following printer types should be recommended?
Computers and Technology
1 answer:
Sergeu [11.5K]2 years ago
7 0

According to the requirements of the client, the printing solution should print three sheets of paper with identical information on each page with a single pass of the printer.

<u>Explanation:</u>

Furthermore, the client requests that it should take the least amount of time and effort to maintain. The printer type according to the requirements should be an impact printer.

Impact printers suit the needs of the client and are easy to maintain due to the low cost. Also, they print by making physical contact with the paper and have a significant speed of printing.

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(NumberFormatException)Write the bin2Dec(String binaryString) method to convert a binary string into a decimal number. Implement
tresset_1 [31]

The following program will be used that prompts the user to enter a binary number as a string and displays decimal equivalent of the string.

<u>Explanation:</u>

NumberFormat.java

import java.util.Scanner;

public class NumberFormat{

public static void main(String[] args) {

      Scanner scan = new Scanner(System.in);

      try{

      System.out.println("Enter a binary string:");

      String s = scan.next();

      int integerValue = bin2Dec(Integer.parseInt(s));

      System.out.println("The decimal value of "+s+" is "+integerValue);

      }

      catch(NumberFormatException e){

          System.out.println(e);

      }

  }  

  public static int bin2Dec(int binaryNumber) throws NumberFormatException{

  int decimal = 0;

  int p = 0;

  try{

  while(true){

  if(binaryNumber == 0){

  break;

  } else {

  int temp = binaryNumber%10;

  decimal += temp*Math.pow(2, p);

  binaryNumber = binaryNumber/10;

  p++;

  }

  }

  }

  catch(NumberFormatException e){

      throw new NumberFormatException("Invalid binary number");

  }

  return decimal;

  }

}

Output:

Enter a binary string:

1011000101

The decimal value of 1011000101 is 709

5 0
2 years ago
A layer 2 switch is used to switch incoming frames from a 1000base-t port to a port connected to a 100base-t network. which meth
fredd [130]
<span>Shared memory buffering would work best. This would give the ports the best allocation of resources, using only those that are the most active and best allocated for the size of the frames being transmitted in the current traffic. In addition, any port can store these frames, instead of being specifically allocated as per other types of memory buffering.</span>
7 0
2 years ago
What best describes the purpose of the Recycle Bin (Microsoft Windows) and Trash (Apple Mac) features
alexandr1967 [171]
Its to delete the files from the computer that you no longer want. Once its put in the recycling bin it stays there, then when you empty it, its off your computer and there is no way you can get those files back. This can also free-up some space from your computer since mega and giga bites are being removed from your computer.
7 0
2 years ago
Read 2 more answers
7.8.1: Function pass by reference: Transforming coordinates. Define a function CoordTransform() that transforms the function's f
Lilit [14]

Answer:

Here is the CoordTransform() function:              

void CoordTransform(int xVal, int yVal, int &xValNew, int &yValNew){

xValNew = (xVal + 1) * 2;

yValNew = (yVal + 1) * 2; }

The above method has four parameters xVal  and yVal that are used as input parameters and xValNew yValNew as output parameters. This function returns void and transforms its first two input parameters xVal and yVal into two output parameters xValNew and yValNew according to the formula: new = (old + 1) *

Here new variables are xValNew  and yValNew and old is represented by xVal and yVal.

Here the variables xValNew and yValNew are passed by reference which means any change made to these variables will be reflected in main(). Whereas variables xVal and yVal are passed by value.

Explanation:

Here is the complete program:

#include <iostream>

using namespace std;

void CoordTransform(int xVal, int yVal, int &xValNew, int &yValNew){

xValNew = (xVal + 1) * 2;

yValNew = (yVal + 1) * 2;}

int main()

{ int xValNew;

int yValNew;

int xValUser;

int yValUser;

cin >> xValUser;

cin >> yValUser;

CoordTransform(xValUser, yValUser, xValNew, yValNew);

cout << "(" << xValUser << ", " << yValUser << ") becomes (" << xValNew << ", " << yValNew << ")" << endl;

return 0; }

The output is given in the attached screenshot   

7 0
2 years ago
Considering the following algorithm, which of the following requirements are satisfied?
Alisiya [41]

Answer:

b) Bounded Waiting

Explanation:

int currentThread = 1;

bool thread1Access = true;

bool thread2Access = true;

thread1 { thread2 {

While (true) {

                   While (true)

                                   {

                     while(thread2Access == true)

                                       {

                                      while(thread1Access == true)

                                       {

                                            If (currentThread == 2) {

                                              If (currentThread == 1)

                                                {        

                                                  thread1Access = false; thread2Access = false;

                                                  While (currentThread == 2);

                                                 While (currentThread == 1);

                                                  thread1Access = true; thread2Access = true;

} }

/* start of critical section */ /* start of critical section */

currentThread = 2 currentThread = 1

… ...

/* end of critical section */ /* end of critical section */

thread1Access = false; thread2Access = false;

… ...

} }

} }

} }

It can be seen that in all the instances, both threads are programmed to share same resource at the same time, and hence this is the bounded waiting. For Mutual exclusion, two threads cannot share one resource at one time. They must share simultaneously. Also there should be no deadlock. For Progress each thread should have exclusive access to all the resources. Thus its definitely the not the Progress. And hence its Bounded waiting.

4 0
2 years ago
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