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Len [333]
2 years ago
9

Considering the following algorithm, which of the following requirements are satisfied?

Computers and Technology
1 answer:
Alisiya [41]2 years ago
4 0

Answer:

b) Bounded Waiting

Explanation:

int currentThread = 1;

bool thread1Access = true;

bool thread2Access = true;

thread1 { thread2 {

While (true) {

                   While (true)

                                   {

                     while(thread2Access == true)

                                       {

                                      while(thread1Access == true)

                                       {

                                            If (currentThread == 2) {

                                              If (currentThread == 1)

                                                {        

                                                  thread1Access = false; thread2Access = false;

                                                  While (currentThread == 2);

                                                 While (currentThread == 1);

                                                  thread1Access = true; thread2Access = true;

} }

/* start of critical section */ /* start of critical section */

currentThread = 2 currentThread = 1

… ...

/* end of critical section */ /* end of critical section */

thread1Access = false; thread2Access = false;

… ...

} }

} }

} }

It can be seen that in all the instances, both threads are programmed to share same resource at the same time, and hence this is the bounded waiting. For Mutual exclusion, two threads cannot share one resource at one time. They must share simultaneously. Also there should be no deadlock. For Progress each thread should have exclusive access to all the resources. Thus its definitely the not the Progress. And hence its Bounded waiting.

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The answer for this would be B.
5 0
2 years ago
Read 2 more answers
Modify the TimeSpan class from Chapter 8 to include a compareTo method that compares time spans by their length. A time span tha
My name is Ann [436]

Answer:

Check the explanation

Explanation:

Here is the modified code for

TimeSpan.java and TimeSpanClient.java.

// TimeSpan.java

//implemented Comparable interface, which has the compareTo method

//and can be used to sort a list or array of TimeSpan objects without

//using a Comparator

public class TimeSpan implements Comparable<TimeSpan> {

   private int totalMinutes;

   // Constructs a time span with the given interval.

   // pre: hours >= 0 && minutes >= 0

   public TimeSpan(int hours, int minutes) {

        totalMinutes = 0;

        add(hours, minutes);

   }

   // Adds the given interval to this time span.

   // pre: hours >= 0 && minutes >= 0

   public void add(int hours, int minutes) {

        totalMinutes += 60 * hours + minutes;

   }

   // Returns a String for this time span such as "6h15m".

   public String toString() {

        return (totalMinutes / 60) + "h" + (totalMinutes % 60) + "m";

   }

   // method to compare this time span with other

   // returns a negative value if this time span is shorter than other

   // returns 0 if both have same duration

   // returns a positive value if this time span is longer than other

   public int compareTo(TimeSpan other) {

        if (this.totalMinutes < other.totalMinutes) {

            return -1; // this < other

        } else if (this.totalMinutes > other.totalMinutes) {

            return 1; // this > other

        } else {

            return 0; // this = other

        }

   }

}

// TimeSpanClient.java

public class TimeSpanClient {

   public static void main(String[] args) {

        int h1 = 13, m1 = 30;

        TimeSpan t1 = new TimeSpan(h1, m1);

        System.out.println("New object t1: " + t1);

        h1 = 3;

        m1 = 40;

        System.out.println("Adding " + h1 + " hours, " + m1 + " minutes to t1");

        t1.add(h1, m1);

        System.out.println("New t1 state: " + t1);

        // creating another TimeSpan object, testing compareTo method using the

        // two objects

        TimeSpan t2 = new TimeSpan(10, 20);

        System.out.println("New object t2: " + t2);

        System.out.println("t1.compareTo(t2): " + t1.compareTo(t2));

        System.out.println("t2.compareTo(t1): " + t2.compareTo(t1));

        System.out.println("t1.compareTo(t1): " + t1.compareTo(t1));

   }

}

/*OUTPUT*/

New object t1: 13h30m

Adding 3 hours, 40 minutes to t1

New t1 state: 17h10m

New object t2: 10h20m

t1.compareTo(t2): 1

t2.compareTo(t1): -1

t1.compareTo(t1): 0

4 0
2 years ago
In this problem we consider sending real-time voice from Host A to Host B over a packet-switched network (VoIP). Host A converts
Minchanka [31]

Answer:

<u>The total time elapsed from the time a bit is created (from the original analog signal at Host A) until the bit is decoded (as part of the analog signal at Host B is </u><u>25.11 ms</u>

Explanation:

Host A first converts the analog signal to a digital 64kbps stream and then groups it into 56-byte packets. The time taken for this can be calculated as:

time taken 1= \frac{Packet Size in Bits}{Bit Rate}

                 = (56 x 8) bits / 64 x 10³ bits/s

                 = 7 x 10⁻³s

time taken 1= 7 ms

The transmission rate of the packet from Host A to Host B is 4 Mbps. The time taken to transfer the packets can be calculated as:

time taken 2= (56 x 8) bits / 4 x 10⁶ bits/s

                    = 1.12 x 10⁻⁴ s

time taken 2= 112 μs

The propagation delay is 18 ms.

To calculate the total time elapsed, we need to add up all the time taken at each individual stage.

<u />Time_{total}<u> = Time taken 1 + Time taken 2 + Propagation Delay</u>

                 = 7 ms + 112 μs + 18 ms

                 = 0.025112 s

Time_{total} = 25.11 ms

5 0
2 years ago
Enter a formula in cell G5 that calculates the difference between the attendance totals for 2018 and 2017. Copy the formula to t
Allushta [10]
This is done by a very simple formula: the only thing you need to type is =x-y where x is the cell that contains the total of 2018 and y being the cell that contains the total for 2017. If both are numeric values you can use the formula = A1-B1 and get your result. Your <span>cells don't have to be in the same order as your formula.</span>
4 0
2 years ago
There is a function we are providing in for you in this problem called square. It takes one integer and returns the square of th
anastassius [24]

Answer:

xyz = 25  

result = square(xyz)

print(result)

The above code assigns the value 25 to variable xyz as 5*5=25. Then next statement is a function call to square() function passing xyz to this function in order to compute the square of 25. The output is:

625

Explanation:

The above code can also be written as:

xyz = 5*5

result = square(xyz)

print(result)

The difference is that xyz is assiged 5*5 which is equal to 25 so the output produced will be the same i.e.  625.

The result variable is used to store the value of square of 25 after the square() method computes and returns the square of 25. So print(result) prints the resultant value stored in the result variable i.e. 625

3 0
2 years ago
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