Answer:
xyz = 25
result = square(xyz)
print(result)
The above code assigns the value 25 to variable xyz as 5*5=25. Then next statement is a function call to square() function passing xyz to this function in order to compute the square of 25. The output is:
625
Explanation:
The above code can also be written as:
xyz = 5*5
result = square(xyz)
print(result)
The difference is that xyz is assiged 5*5 which is equal to 25 so the output produced will be the same i.e. 625.
The result variable is used to store the value of square of 25 after the square() method computes and returns the square of 25. So print(result) prints the resultant value stored in the result variable i.e. 625
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Base on the question, and in my further computation, the possible answers would be the following and I hope you are satisfied with my answer and feel free to ask for more.
- If you want to determine the Thevenin equivalent voltage and resistance without overloading the battery, then apply some known resistance
<span><span>RL</span><span>RL</span></span> and measure the output voltage as <span><span>VL</span><span>VL</span></span>. Measure the voltage without a load as <span><span>V<span>OC</span></span><span>V<span>OC</span></span></span>. The voltage divider equation tells us that
<span><span><span>VL</span>=<span>V<span>OC</span></span><span><span>RL</span><span><span>R<span>TH</span></span>×<span>RL</span></span></span></span><span><span>VL</span>=<span>V<span>OC</span></span><span><span>RL</span><span><span>R<span>TH</span></span>×<span>RL</span></span></span></span></span>
Solve for <span><span>R<span>TH</span></span><span>R<span>TH</span></span></span>, and you know that <span><span><span>V<span>TH</span></span>=<span>V<span>OC</span></span></span><span><span>V<span>TH</span></span>=<span>V<span>OC</span></span></span></span>.
