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GuDViN [60]
2 years ago
6

Two devices are connected to the Internet and communicating with one another. A squirrel chews through one of the wires in the n

etwork that is currently being used by the devices to communicate. The network immediately begins using a different path through the network and communication continues as normal.
This situation best exemplifies which principle?
Computers and Technology
1 answer:
bearhunter [10]2 years ago
5 0

Answer:

Fault-Tolerance

Explanation:

Fault tolerance refers to the ability of a system (computer, network, cloud cluster, etc.) to continue operating without interruption when one or more of its components fail.

You might be interested in
A ______________ deals with the potential for weaknesses within the existing infrastructure to be exploited.
algol [13]

Answer:

Threat assessment

Explanation:

A threat assessment deals with the potential for weaknesses within the existing infrastructure to be exploited.

Threat Assessment is further explained as the practice of determining or ascertaining the credibility and seriousness of a potential threat, and also the probability or chases of the threat will becoming a reality.

Threat assessment is separate to the more established procedure of violence-risk assessment, which seek to forcast an individual's general capacity and tendency to respond to situations violently. Instead, threat assessment aims to interrupt people on a route to commit "predatory or instrumental violence, the type of behavior connected with targeted attacks".

3 0
2 years ago
Read 2 more answers
Consider a disk that rotates at 3600 rpm. The seek time to move the head between adjacent tracks is 2 ms. There are 32 sectors p
jasenka [17]

Answer:

19.71 ms

Explanation:

The disk rotates at 3600 rpm, hence the time for one revolution = 60 / 3600 rpm = 16.67 ms.

Hence time to read or write on a sector = time for one revolution / number of sectors per track = 16.67 ms / 32 sectors = 0.52 ms

Head movement time from track 8 to track  9 = seek time = 2 ms

rotation time to head up sector 1 on track 8 to sector 1 on track 9 = 16.67 * 31/32 = 16.15 ms

The total time = sector read time +head movement time + rotational delay + sector write time = 0.52 ms + 2 ms + 16.15 ms + 0.52 ms = 19.19 ms

3 0
2 years ago
To explain acceptable computer use to their employees, students, or other users, many organizations and educational institutions
docker41 [41]

Answer:

Codes of conduct

Explanation:

Codes of conduct are a set of rules or norms established by an organization for all employees, students or users, to ensure individual responsibilities and proper practices. The code of conduct can cover overall behaviour of individuals in an organization, but a specific code of conduct can be developed for proper computer use in order to establish what is appropriate and available to use in the organization´s computers, and also to restrict or avoid non related content.

7 0
1 year ago
Read 2 more answers
The data in a data warehouse have which of the following characteristics?
Burka [1]

Answer: Option(d) is correct

Explanation:

Data warehouse is the storage that holds collected information and data for making acknowledged decision through analyzing the data. Data present in data warehouse is as per subject which contains history and sources of data for understanding and perceiving it.

  • Other options are incorrect because data is not coded in various forms,retrieved for certain period of time, real-time update and arrangement in hierarchical form.
  • Thus, the correct option is option(d).
6 0
2 years ago
2.4: Star Pattern Write a program that displays the following pattern: * *** ***** ******* ***** *** * Output. Seven lines of ou
adelina 88 [10]

Answer:

// here is code in java.

public class NAMES

{

// main method

public static void main(String[] args)

{

int n=4;

// print the upper half

for(int a=1;a<=n;a++)

{

for(int b=1;b<=n-a;b++)

{

// print the spaces

System.out.print(" ");

}

// print the * of upper half

for(int x=1;x<=a*2-1;x++)

{

// print the *

System.out.print("*");

}

// print newline

System.out.println();

}

// print the lower half

for(int y=n-1;y>0;y--)

{

for(int z=1;z<=n-y;z++)

{

// print the spaces

System.out.print(" ");

}

for(int m=1;m<=y*2-1;m++)

{

// print the *

System.out.print("*");

}

// print newline

System.out.println();

}

}

}

Explanation:

Declare a variable "n" and initialize it with 4. First print the spaces (" ") of the upper half with the help of nested for loop.Then print the "*" of the upper half with for loop. Similarly print the lower half in revers order. This will print the required shape.

Output:

  *

 ***

*****

*******

*****

 ***

  *

5 0
2 years ago
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