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Arlecino [84]
2 years ago
12

Driving is expensive. Write a program with a car's miles/gallon and gas dollars/gallon (both floats) as input, and output the ga

s cost for 10 miles, 50 miles, and 400 miles.
Ex: If the input is 20.0 3.1599, the output is:

1.57995 7.89975 63.198

Needs to be in Coral language
Computers and Technology
2 answers:
Tems11 [23]2 years ago
8 0

Answer:

def driving_cost(driven_miles, miles_per_gallon, dollars_per_gallon):

  gallon_used = driven_miles / miles_per_gallon

  cost = gallon_used * dollars_per_gallon  

  return cost  

miles_per_gallon = float(input(""))

dollars_per_gallon = float(input(""))

cost1 = driving_cost(10, miles_per_gallon, dollars_per_gallon)

cost2 = driving_cost(50, miles_per_gallon, dollars_per_gallon)

cost3 = driving_cost(400, miles_per_gallon, dollars_per_gallon)

print("%.2f" % cost1)

print("%.2f" % cost2)

print("%.2f" % cost3)

Explanation:

Ierofanga [76]2 years ago
6 0

Answer:

x^{2} \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \int\limits^a_b {x} \, dx  \lim_{n \to \infty} a_n \sqrt{x} \sqrt[n]{x} \pi \alpha \frac{x}{y} x_{123} \beta

Explanation:

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There are two methods of enforcing the rule that only one device can transmit. In the centralized method, one station is in cont
Levart [38]

Answer:

In centralized method, the authorized sender is known, but the transmission line is dominated by the control station, while in decentralized method, one station can not dominate the line but collision on the transmission line may occur.

Explanation:

Centralized method of communication requires for a control station to manage the activities if other stations in the network. It assigns turns to one known station at a time, for transmission.

Decentralized method allows stations in a network to negotiate and take turns in transmitting data. When a station is done with the transmission line, another station on the queue immediately claims the line.

3 0
2 years ago
Given two integers as user inputs that represent the number of drinks to buy and the number of bottles to restock, create a Vend
ivann1987 [24]

Answer:

In C++:

#include <iostream>

using namespace std;

class VendingMachine {

 public:

   int initial = 20;};

int main() {

 VendingMachine myMachine;

   int purchase, restock;

   cout<<"Purchase: ";  cin>>purchase;

   cout<<"Restock: ";  cin>>restock;

   myMachine.initial-=(purchase-restock);

   cout << "Inventory: "<<myMachine.initial<<" bottles";  

   return 0;}

Explanation:

This question is incomplete, as the original source file is not given; so, I write another from scratch.

This creates the VendingMachine class

class VendingMachine {

This represents the access specifier

 public:

This initializes the inventory to 20

   int initial = 20;};

The main begins here

int main() {

This creates the object of the VendingMachine class

 VendingMachine myMachine;

This declares the purchase and the restock

   int purchase, restock;

This gets input for purchase

   cout<<"Purchase: ";  cin>>purchase;

This gets input for restock

   cout<<"Restock: ";  cin>>restock;

This calculates the new inventory

   myMachine.initial-=(purchase-restock);

This prints the new inventory

   cout << "Inventory: "<<myMachine.initial<<" bottles";  

   return 0;}

8 0
2 years ago
In the process of retrieving a specific memory from a web of associations a person needs to activate one of the strands that lea
iVinArrow [24]

Answer:

Priming.

Explanation:

The brain is the centre of control for all animals. It coordinates the body system, breathing, beating of the heart, memory, gait, speech, sight etc.

Memory is stored in the brain ( the function of the cerebral cortex in the cerebrum). Two types of memory are the long term and the short term memory. The long term memory stores information permanently in the brain, while the short term holds the information for a while and either transfers it to the long term memory or the memory decays.

To retrieve a specific memory from the wide memory of the brain, it activates a strand that leads to the memory, this process is called priming.

6 0
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The it department is reporting that a company web server is receiving an abnormally high number of web page requests from differ
Talja [164]
<span>In the scenario in which the IT department is reporting that a company web server is receiving an abnormally high number of web page requests from different locations simultaneously the DDoS security attack is occurring.
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8 0
2 years ago
Complete function PrintPopcornTime(), with int parameter bagOunces, and void return type. If bagOunces is less than 3, print "To
SVETLANKA909090 [29]

Answer:

<h2>Function 1:</h2>

#include <stdio.h> //for using input output functions

// start of the function PrintPopcornTime body having integer variable //bagOunces as parameter

void PrintPopcornTime(int bagOunces){

if (bagOunces < 3){ //if value of bagOunces is less than 3

 printf("Too small"); //displays Too small message in output

 printf("\n"); } //prints a new line

//the following else if part will execute when the above IF condition evaluates to //false and the value of bagOunces is greater than 10

else if (bagOunces > 10){

    printf("Too large"); //displays the message:  Too large in output

    printf("\n"); //prints a new line }

/*the following else  part will execute when the above If and else if conditions evaluate to false and the value of bagOunces is neither less than 3 nor greater than 10 */

else {

/* The following three commented statements can be used to store the value of bagOunces * 6 into result variable and then print statement to print the value of result. The other option is to use one print statement printf("%d",bagOunces * 6) instead */

    //int result;

    //result = bagOunces * 6;

    //printf("%d",result);

 printf("%d",bagOunces * 6);  /multiplies value of bagOunces  to 6

 printf(" seconds");

// seconds is followed with the value of bagOunces * 6

 printf("\n"); }} //prints a new line

int main(){ //start of main() function body

int userOunces; //declares integer variable userOunces

scanf("%d", &userOunces); //reads input value of userOunces

PrintPopcornTime(userOunces);

//calls PrintPopcornTime function passing the value in userOunces

return 0; }

Explanation:

<h2>Function 2:  </h2>

#include <stdio.h> //header file to use input output functions

// start of the function PrintShampooInstructions body having integer variable numCycles as parameter

void PrintShampooInstructions(int numCycles){

if(numCycles < 1){

//if conditions checks value of numCycles is less than 1 or not

printf("Too few."); //prints Too few in output if the above condition is true

printf("\n"); } //prints a new line

//else if part is executed when the if condition is false and else if  checks //value of numCycles is greater than 4 or not

else if(numCycles > 4){

//prints Too many in output if the above condition is true

printf("Too many.");

printf("\n"); } //prints a new line

//else part is executed when the if and else if conditions are false

else{

//prints "N: Lather and rinse." numCycles times, where N is the cycle //number, followed by Done

for(int N = 1; N <= numCycles; N++){

printf("%d",N);

printf(": Lather and rinse. \n");}

printf("Done.");

printf("\n");} }

int main() //start of the main() function body

{    int userCycles; //declares integer variable userCycles

   scanf("%d", &userCycles); //reads the input value into userCycles

   PrintShampooInstructions(userCycles);

//calls PrintShampooInstructions function passing the value in userCycles

   return 0;}

I will explain the for loop used in PrintShampooInstructions() function. The loop has a variableN  which is initialized to 1. The loop checks if the value of N is less than or equal to the value of numCycles. Lets say the value of numCycles = 2. So the condition evaluates to true as N<numCycles  which means 1<2. So the program control enters the body of loop. The loop body has following statements. printf("%d",N); prints the value of N followed by

printf(": Lather and rinse. \n"); which is followed by printf("Done.");

So at first iteration:

printf("%d",N); prints 1 as the value of N is 1

printf(": Lather and rinse. \n");  prints : Lather and rinse and prints a new line \n.

As a whole this line is printed on the screen:

1: Lather and rinse.

Then the value of N is incremented by 1. So N becomes 2 i.e. N = 2.

Now at second iteration:

The loop checks if the value of N is less than or equal to the value of numCycles. We know that the value of numCycles = 2. So the condition evaluates to true as N<numCycles  which means 2=2. So the program control enters the body of loop.

printf("Done."); prints Done after the above two lines.

printf("%d",N); prints 2 as the value of N is 2

printf(": Lather and rinse. \n");  prints : Lather and rinse and prints a new line \n.

As a whole this line is printed on the screen:

2: Lather and rinse.

Then the value of N is incremented by 1. So N becomes 2 i.e. N = 3.

The loop again checks if the value of N is less than or equal to the value of numCycles. We know that the value of numCycles = 2. So the condition evaluates to false as N<numCycles  which means 3>2. So the loop breaks.

Now the next statement is:

printf("Done."); which prints Done on the screen.

So as a whole the following output is displayed on the screen:

1: Lather and rinse.

2: Lather and rinse.

Done.

The programs along with their outputs are attached.

6 0
2 years ago
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