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2 years ago

Illustrate why Sally's slide meets or does not meet professional expectations?

Computers and Technology

1 answer:

givi [52]2 years ago

5 0

The correct answer to this open question is the following.

Unfortunately, you did not provide any context or background about the situation of Sally and the problem with her slides. We do not know it, just you.

However, trying to be of help, we can comment on the following general terms.

When someone does not meet professional expectations, this means that this individual did not prepare her presentation, lacked technical skills, did not included proper sources, or missed the proper visual aids to make the presentation more attractive and dynamic.

What Sally can improve about her slides is the following.

She can design a better structure for the presentation to have more congruence.

Sally has to clearly establish the goal or goals for her presentation.

She has to add many visuals instead of plain text. This way she can better capture the interest of her audience.

If she can use more vivid colors instead of pale or dark ones, that would be best.

No paragraphs unless necessary. She better uses bullet points.

Take care of the tone of her voice. During her practice, she can record her vice to check how it sounds.

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Which telecommunications device is widely used in industries that require closed communication?

Stella [2.4K]

The telecommunications device that is widely used in industries that require closed communication are walkie-talkies. Correct answer: D

Walkie-talkies are hand-held, portable, two-way radio transceivers which enable secure communication between the two points, without being part of a network.

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2 years ago

Read 2 more answers

A process is moved to wait queue when I/O request is made with:_______ A. non-blocking I/O B. blocking I/O C. asynchronous I/O D

Sidana [21]

Answer:

B. blocking I/O

Explanation:

Most of the input and output request placed to the computer considers the blocking request. It means that the controls given cannot be returned to the given application until and unless the input/output is complete.

Thus, blocking the input/output does not return till the input and output is complete.

With a blocking I/O, the process is moved to a wait queue when the I/O request is made, and it moved backs to the ready queue as soon as the request is complete, thereby allowing the other processes to run in the meantime.

Thus (B) blocking I/O is the answer.

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2 years ago

Cardinality ratios often dictate the detailed design of a database. The cardinality ratio depends on the real-world meaning of t

Otrada [13]

Solution :

ENTITY 1 CARDINALITY RATIO ENTITY 2

1. Student 1 to many Social security card

A student may have more than one

social security card (legally with the

same unique social security number),

and every social security number belongs

to a unique.

2. Student Many to Many Teacher

Generally students are taught by many

teachers and a teacher teaches many students.

3.ClassRoom Many to Many Wall

Do not forget that the wall is usually

shared by adjacent rooms.

4. Country 1 to 1 Current President

Assuming a normal country under normal

circumstances having one president at a

time.

5. Course Many to Many TextBook

A course may have many textbooks and

text book may be prescribed for different

courses.

6. Item Many to Many Order

Assuming the same item can appear

in different orders.

7. Student Many to Many Class

One student may take several classes.

Every class usually has several students.

8. Class Many to 1 Instructor

Assuming that every class has a unique

instructor. In case instructors were allowed

to team teach, this will be many-many.

9. Instructor 1 to 1 Office

Assuming every instructor has only one

office and it is not shared. In case of offices

shared by 2 instructors, the relationship

will be 2-1. Conversely, if any instructor has a joint

appointment and offices in both departments,

then the relationship will be 1-2. In a very general

case, it may be many-many.

10. E-bay Auction item 1-Many E-bay bid

1 item has many bids and a bid is unique

to an item.

7 0

2 years ago

A hidden backlog contains the projects that the IT department is not aware of because of low feasibility.

Finger [1]

Answer: True

Explanation:

Yes, the given statement is true that the due to the very low feasibility the IT (Information technology) department are not aware of the hidden backlog that basically contain projects.

The feasibility is the main factor in the IT department as it helps to study whole objective of the project and then also uncover all the strength and weakness of the project so that we can easily go through the details to make the project more efficient and reliable.

8 0

2 years ago

There are N bulbs numbered from 1 to N, arranged in a row. The first bulb is plugged into the power socket and each successive b

Ksivusya [100]

Answer:

The code is given below with appropriate comments

Explanation:

// TestSolution class implementation

import java.util.Arrays;

public class TestSolution

{

// solution function implementation

public static int solution(int[] arr)

{

// declare the local variables

int i, j, count = 0;

boolean shines;

// use the nested loops to count the number of moments for which every turned on bulb shines

for (i = 0; i < arr.length; i++)

{

shines = true;

for (j = i + 1; j < arr.length && shines; j++)

{

if (arr[i] > arr[j])

shines = false;

}

if (shines)

count++;

}

// return the number of moments for which every turned on bulb shines

return count;

} // end of solution function

// start main function

public static void main(String[] args)

{

// create three arrays named A, B, and C

int[] A = {2, 1, 3, 5, 4};

int[] B = {2, 3, 4, 1, 5};

int[] C = {1, 3, 4, 2, 5};

// generate a random number N within the range range[1..100000]

int N = 1 + (int)(Math.random() * 100000);

// create an array named D of size N

int[] D = new int[N];

// fill the array D with the distinct random numbers within the range [1..N]

int i = 0;

while(i < N)

{

int num = 1 + (int)(Math.random() * N);

boolean found = false;

for(int j = 0; j < i && !found; j++)

{

if(D[j] == num)

found = true;

}

if(!found)

{

D[i] = num;

i++;

}

// print the elements and number of moments of the arrays A, B, and C

System.out.println("Array A: " + Arrays.toString(A) + " and Moments: " + solution(A));

System.out.println("Array B: " + Arrays.toString(B) + " and Moments: " + solution(B));

System.out.println("Array C: " + Arrays.toString(C) + " and Moments: " + solution(C));

// print the size and number of moments of the array D

System.out.println("Size(N) of Array D: " + N + " and Moments: " + solution(D));

} // end of main function

} // end of TestSolution class

3 0

2 years ago