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DENIUS [597]
2 years ago
10

Fill in the blanks to make the print_prime_factors function print all the prime factors of a number prime factor is a number tha

t is prime and divides another without a remainder.
def print_prime_factors(number):
# Start with two, which is the first prime
factor = 2
# Keep going until the factor is larger than the number
while factor <= number:
# Check if factor is a divisor of number
if number % factor == ___:
# If it is, print it and divide the original number
print(factor)
number = number / factor
else:
# If it's not, increment the factor by one ___
return "Done"
print_prime_factors(100) # Should print 2,2,5,5

Computers and Technology
1 answer:
fomenos2 years ago
3 0

The answer & explanation for this question is given in the attachment below.

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Which of the following describes an executive information system (EIS)?
rjkz [21]
I think the answer is b

hope this helps :)
3 0
2 years ago
Use the ________ method to write text to a web page.
Nastasia [14]
Document.write()

I'm not sure that this is a method, but I think this is right. 
3 0
2 years ago
Define a method calcPyramidVolume with double data type parameters baseLength, baseWidth, and pyramidHeight, that returns as a d
enyata [817]

Answer:

The method in C++ is as follows:

double calcPyramidVolume(double baseLength, double baseWidth, double pyramidHeight){

   double baseArea = calcBaseArea(baseLength, baseWidth);

   double volume = baseArea * pyramidHeight;

   return volume;    

}

Explanation:

This defines the calcPyramidVolume method

double calcPyramidVolume(double baseLength, double baseWidth, double pyramidHeight){

This calls the calcBaseArea method to calculate the base area of the pyramid

   double baseArea = calcBaseArea(baseLength, baseWidth);

This calculates the volume

   double volume = baseArea * pyramidHeight;

This returns the volume

   return volume;  

}

<em>See attachment for complete program that include all methods that is required for the program to function.</em>

5 0
2 years ago
In this assignment you'll write a program that encrypts the alphabetic letters in a file using the Vigenère cipher. Your program
solniwko [45]

Answer:

C code is given below

Explanation:

// Vigenere cipher

#include <ctype.h>

#include <stdio.h>

#include <stdlib.h>

#include <string.h>

/**

* Reading key file.

*/

char *readFile(char *fileName) {

   FILE *file = fopen(fileName, "r");

   char *code;

   size_t n = 0;

   int c;

   if (file == NULL) return NULL; //could not open file

   code = (char *)malloc(513);

   while ((c = fgetc(file)) != EOF) {

      if( !isalpha(c) )

          continue;

      if( isupper(c) )

          c = tolower(c);

      code[n++] = (char)c;

   }

   code[n] = '\0';

  fclose(file);

   return code;

}

int main(int argc, char ** argv){  

   // Check if correct # of arguments given

   if (argc != 3) {

       printf("Wrong number of arguments. Please try again.\n");

       return 1;

   }

 

  // try to read the key file

  char *key = readFile(argv[1]);

  if( !key ) {

      printf( "Invalid file %s\n", argv[1] );

      return 1;

  }

 

  char *data = readFile(argv[2]);

  if( !data ) {

      printf("Invalid file %s\n", argv[2] );

      return 1;

  }

 

   // Store key as string and get length

   int kLen = strlen(key);

  int dataLen = strlen( data );

 

  printf("%s\n", key );

  printf("%s\n", data );

 

  int paddingLength = dataLen % kLen;

  if( kLen > dataLen ) {

      paddingLength = kLen - dataLen;

  }

  for( int i = 0; i < paddingLength && dataLen + paddingLength <= 512; i++ ) {

      data[ dataLen + i ] = 'x';

  }

 

  dataLen += paddingLength;

 

   // Loop through text

   for (int i = 0, j = 0, n = dataLen; i < n; i++) {          

       // Get key for this letter

       int letterKey = tolower(key[j % kLen]) - 'a';

     

       // Keep case of letter

       if (isupper(data[i])) {

           // Get modulo number and add to appropriate case

           printf("%c", 'A' + (data[i] - 'A' + letterKey) % 26);

         

           // Only increment j when used

           j++;

       }

       else if (islower(data[i])) {

           printf("%c", 'a' + (data[i] - 'a' + letterKey) % 26);

           j++;

       }

       else {

           // return unchanged

           printf("%c", data[i]);

       }

      if( (i+1) % 80 == 0 ) {

          printf("\n");

      }

   }

 

   printf("\n");

 

   return 0;

}

4 0
2 years ago
Read 2 more answers
REST Basics REST is a protocol and a set of operations that many web services conform to in order to exchange information and in
vekshin1

Answer:

The answer is "Option A and Option C".

Explanation:

In choice a, it is true since a client-server design can be used for REST-application. A user is somebody who needs space and it doesn't deal with storing data on a central computer. A client is someone with the money, and the interface does not. Its server doesn't want to worry regarding core functionality on the ends of the server. The server does not have to know anything at all about the layer of UI used at the end of the server.

In choice c, it is true As just a Web app, services like corporate/employee resources must be organized, and HTTP verbs like the GET, Place, POST, DELETE must be used to modify these. It must be obvious, as a programmer, that what is required is clearly to look only at the interface or HTTP method used.

7 0
2 years ago
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