Answer: provided in the explanation segment
Explanation:
This looks a bit confusing but you can follow through using the provided code.
/*
Line 1. x at %ebp+8, y at %ebp+12, z at %ebp+16
Line 2. movl 12(%ebp), %edx
Line 3. subl 16(%ebp), %edx
Line 4. movl %edx, %eax
Line 5. sall $31, %eax
Line 6. sarl $31, %eax
Line 7. imull 8(%ebp), %edx
Line 8. xorl %edx, %eax
*/
#include<stdio.h>
// function decode above program
int decode2(int x,int y,int z){
// In Line 2 y is stored in variable
int var1 = y;
// In Line 3 subtract z from var1 and store in var1
var1 = var1 - z;
// In Line 4 move var1 value to another value count
int count = var1;
// In Line 5 left shift by 31 value in count
count<<31;
// In Line 6 right shift by 31 value in count
count>>31;
// In Line 7 multiply x with value in var1
var1 = var1*x;
// In Line 8 xor the var1 and count and store in count
count = var1 ^ count;
// return count;
return count;
}
// main function for testing
int main(){
printf("Enter the value of x ");
int x;
scanf("%d",&x);
printf("Enter the value of y ");
int y;
scanf("%d",&y);
printf("Enter the value of z ");
int z;
scanf("%d",&z);
printf("value of decode2(%d,%d,%d) is %d\n",x,y,z,decode2(x,y,z));
return 0;
}
cheers i hope this helps
