Answer:
SSL has operate in Application Layer to encrypt the information from user and pass it to the TCP. To enhance TCP security developer can integrate the code of SSL with application layer.
Explanation:
SSL certificate is used to enhance the security of user data and encrypt the information of passwords, data transfer and other information to make it secure. This certificate is installed at application layer to make all the information secure and send it to the Transmission Control Protocol (TCP) to send it further. The TCP can be enhanced more by adding SSL code to the application Layer of the Network.
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Answer:
(a)Applications Time Stamp Events
(b)S=0.5(W-
)+
, where
≤W≤
+8.
Explanation:
Some applications assume that clocks always advance, so they could timestamp events under this assumption.
In our case we have the wrong timed clock, say W and the hardware clock H which is supposed to advance at a perfect rate.
We proceed to construct a software clock such that after 8 seconds we can replace the wrong timed clock with the software clock in good conditions.
Let us denote the software clock with S.
Then, S=c(W-
)+
where:
=The current Time(10:27:54) and;
c is to be found.
We already know that S=
+4 when W=
+8,
So:
S=c(W-
)+
+4=c(
+8-
)+
4=8c
c=0.5
We obtain the formula
S=0.5(W-
)+
, where
≤W≤
+8.
Answer:
See explaination
Explanation:
public class PalindromeChange {
public static void main(String[] args) {
System.out.println("mom to non palindrom word is: "+changTONonPalindrom("mom"));
System.out.println("mom to non palindrom word is: "+changTONonPalindrom("aaabbaaa"));
}
private static String changTONonPalindrom(String str)
{
int mid=str.length()/2;
boolean found=false;
char character=' ';
int i;
for(i=mid-1;i>=0;i--)
{
character = str.charAt(i);
if(character!='a')
{
found=true;
break;
}
}
if(!found)
{
for(i=mid+1;i<str.length();i++)
{
character = str.charAt(i);
if(character!='a')
{
found=true;
break;
}
}
}
// This gives the character 'a'
int ascii = (int) character;
ascii-=1;
str = str.substring(0, i) + (char)ascii+ str.substring(i + 1);
return str;
}
}
we translate the following statement given in terms of logarithms. 211 base x can be expressed into log 211 / log x while 152 base 8 can be expressed int o log 152 over log 8. In this case,
log 211 / log x = log 152 / log 8log x = 0.962x = 10^0.962 = 9.1632