Evaluate \dfrac13m-1-\dfrac12n 3 1 m−1− 2 1 nstart fraction, 1, divided by, 3, end fraction, m, minus, 1, minus, start fract
2 answers:
Answer:
Step-by-step explanation:
Given the following expression:
You know that the value of "m" is:
And the value of "n" is:
Knowing these values, you must substitute them into the given expression:
So, in order to evaluate, the first step is to solve the multiplications and then you must reduce the fractions. Then:
Now, you must solve the subtraction.
You get that the difference (which is the result of the subtraction) is the following:
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Answer:
The confidence interval on this case is given by:
(1)
For this case the confidence interval is given by (62.532, 76.478)[/tex]
And we can calculate the mean with this:
So then the mean for this case is 69.505
Step-by-step explanation:
Previous concepts
The margin of error is the range of values below and above the sample statistic in a confidence interval.
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".
represent the sample mean
population mean (variable of interest)
represent the population standard deviation
n represent the sample size
Assuming the X follows a normal distribution
The confidence interval on this case is given by:
(1)
For this case the confidence interval is given by (62.532, 76.478)[/tex]
And we can calculate the mean with this:
So then the mean for this case is 69.505