We know that
The volume of a circular truncated cone=(1/3)*pi*[r1²+r1*r2+r2²]*h
where
r1=7/2-----> 3.5 in
r2=10/2----> 5 in
h=12 in
volume of a circular truncated cone=(1/3)*pi*[3.5²+3.5*5+5²]*12
volume=688 in³
the answer is
688 in³
9 + 1.34 + 1 2 (3.50 +1.74)
Step 1: add what is inside the parenthesis
9 + 1.34 + 1 2 (5.24)
Step 2: multiply what is inside the parenthesis by 12.
9 + 1.34 + 62.88
Step 3: Add all the numbers
73.22
answer
9 + 1.34 + 1 2 (3.50 +1.74) = 73.22
Answer:
-$100
Step-by-step explanation:
If Amy subtracted $5 from her bank balance 20 times, it is ...
$5 × 20 = $100
<em>less</em> than it was.
The amount of change totaled -$100.
<em>Answer:</em>
Complete proof is written below.
Facts and explanation about the segments shown in question :
- As BC = EF is a given statement in the question
- AB + BC = AC because the definition of betweenness gives us a clear idea that if a point B is between points A and C, then the length of AB and the length of BC is equal to the length of AC. Also according to Segment addition postulate, AB + BC = AC. For example, if AB = 5 and BC= 7 then AC = AB + BC → AC = 12
- AC > BC because the Parts Theorem (Segments) mentions that if B is a point on AC between A and C, then AC > BC and AC>AB. So, if we observe the question figure, we can realize that point B lies on the segment AC between points A and C.
- AC > EF because BC is equal to EF and if AC>BC, then it must be true that the length of AC must greater than the length segment EF.
Below is the complete proof of the observation given in the question:
<em />
<em>STATEMENT REASON </em>
___________________________________________________
1. BC = EF 1. Given
2. AB + BC = AC 2. Betweenness
3. AC > BC 3. Def. of segment inequality
4. AC > EF 4. Def. of congruent segments
<em />
<em>Keywords: statement, length, reason, proof</em>
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Answer:
Volume of this cylinder = 785.71 Cm³
Surface area of this cylinder = 157.14 Cm²
Step-by-step explanation:
Given:
Height of cylinder = 10 Cm
Radius of cylinder = 10 / 2 = 5 Cm
Find:
Volume of this cylinder.
Surface area of this cylinder
Computation:
Volume of this cylinder = πr²h
Volume of this cylinder = (22/7)(5)²(10)
Volume of this cylinder = 785.71 Cm³
Surface area of this cylinder = 2πr(h+r)
Surface area of this cylinder = 2(22/7)(5)(10+5)
Surface area of this cylinder = 2(22/7)(5)(15)
Surface area of this cylinder = 157.14 Cm²