Circle J is located in the first quadrant with center (a, b) and radius s. Felipe transforms Circle J to prove that it is simila
1 answer:
You might be interested in
(5.75,0)
Let A be (x1,y1) , B be (x2,y2) , P be (x,y) and the ratio be m:n
Formula is,
x=(x2*m+x1*n)/(m+n)
y=(y2*m+y1*n)/(m+n)
Answer:
(a) The distribution of <em>X</em> is <em>N</em> (9.8, 0.8²).
(b) The probability that an American consumes between 8.8 and 9.9 grams of sodium per day is 0.4461.
(c) The middle 30% of American men consume between 9.5 grams to 10.1 grams of sodium.
Step-by-step explanation:
The random variable <em>X</em> is defined as the amount of sodium consumed.
The random variable <em>X</em> has an average value of, <em>μ</em> = 9.8 grams.
The standard deviation of <em>X</em> is, <em>σ</em> = 0.8 grams.
(a)
It is provided that the sodium consumption of American men is normally distributed.
The random variable <em>X</em> follows a normal distribution with parameters <em>μ</em> = 9.8 grams and <em>σ</em> = 0.8 grams.
Thus, the distribution of <em>X</em> is <em>N</em> (9.8, 0.8²).
(b)
If X ~ N (µ, σ²), then , is a standard normal variate with mean, E (Z) = 0 and Var (Z) = 1. That is, Z ~ N (0, 1).
To compute the probability of Normal distribution it is better to first convert the raw score (<em>X</em>) to <em>z</em>-scores.
Compute the probability that an American consumes between 8.8 and 9.9 grams of sodium per day as follows:
Thus, the probability that an American consumes between 8.8 and 9.9 grams of sodium per day is 0.4461.
(c)
The probability representing the middle 30% of American men consuming sodium between two weights is:
Compute the value of <em>z</em> as follows:
The value of <em>z</em> for P (Z < z) = 0.65 is 0.39.
Compute the value of <em>x</em>₁ and <em>x</em>₂ as follows:
Thus, the middle 30% of American men consume between 9.5 grams to 10.1 grams of sodium.