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Nitella [24]
2 years ago
12

Prove the diagonals of the square with vertices P(0, 4), Q(4, 4), R(0, 0), and S(4, 0) are perpendicular bisectors of each other

. Step 1: Calculate the slope of the diagonals. The slope of diagonal PS is . The slope of diagonal QR is . Step 2: Calculate the midpoint of the diagonals. The midpoint of PS is . The midpoint of QR is . The diagonals of the square are perpendicular bisectors because the diagonals are .
Mathematics
2 answers:
Soloha48 [4]2 years ago
7 0

Answer:

i did the assignment on edge, i hope this helps!   :)

Step-by-step explanation:

On a coordinate plane, square P Q R S is shown. It has points (0, 4), (4, 4), (0, 0), and (4, 0).

Prove the diagonals of the square with vertices P(0, 4), Q(4, 4), R(0, 0), and S(4, 0) are perpendicular bisectors of each other.

Step 1: Calculate the slope of the diagonals.

The slope of diagonal PS is .  -1

The slope of diagonal QR is .  1

Step 2: Calculate the midpoint of the diagonals.  

The midpoint of PS is .  (2,2)

The midpoint of QR is .  (2,2)

The diagonals of the square are perpendicular bisectors because the diagonals are . perpendicular and share the same midpoint

const2013 [10]2 years ago
6 0

Answer:

The slope of diagonal PS is -1.

The slope of diagonal QR is 1.

The midpoint of PS is (2, 2).

The midpoint of QR is (2, 2).

Perpendicular and share the same midpoint.

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Answer:

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Step-by-step explanation:

Recall that rate involve quotient of the two quantities in question:

Then cups of flour per cups of water is the quotient: 2 cups of flour divided by 1/3 cup of water:

\frac{2}{\frac{1}{3} } =2\,*\,\frac{3}{1} = 6

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Match each three-dimensional figure to its volume based on the given dimensions. (Assume π = 3.14.)
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Answer:

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The volume of the pyramid is 160 cm³ ⇒ 2nd answer

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Step-by-step explanation:

* Lets revise the volumes of some shapes

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- The volume of the pyramid is:

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∵ V = 1/3 π r² h

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∵ r = 5 cm , h = 12 cm

∴ V = 1/3 (3.14) (5)² (12) = 314 cm³

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∵ The height = 30 cm

∴ V = 1/3 (16) (30) = 160 cm³

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# A pyramid with square base of length 3 cm and height 16 cm

∵  V = 1/3 × its base area × its height

∵ The area of the square = s²

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Answer:

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b-Check illustration  below

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Step-by-step explanation:

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b. To test for hypothesis:-

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H_0:p_1=p_2\\H_A=p_1\neq p_2\\\alpha=0.05

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(\bar p_1-\bar p_2)\pm Z_0_._5_\alpha \times \sqrt   \frac{ \bar p_1(1-\bar p_1)}{n_1}+\frac{\bar p_2(1-\bar p_2)}{n_2}\\\\=(0.05-0.067)\pm 1.645  \times \sqrt \ \frac{0.05+0.95}{200}+\frac{0.067+0.933}{300}\\

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*CI contains o, which implies that proportions are NOT significantly different.

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