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vesna_86 [32]
2 years ago
12

A golf course in Phoenix, Arizona, uses an average of 80 million gallons of water daily for irrigation. An average family of fou

r (also living in Phoenix, AZ) uses 325,851 gallons of water per year. Rounded to the nearest ten, how many families of four can one golf course provide water for?
Mathematics
2 answers:
Ymorist [56]2 years ago
7 0

Answer:

<h2>89610 family</h2><h2 />

Step-by-step explanation:

An average family of four (also living in Phoenix, AZ) uses 325,851÷365 gallons of water per day

then

An average family of four (also living in Phoenix, AZ) uses 892.74247 gallons of water per day

therefore

the number of families of four can one golf course provide water for :

80 000 000÷892.74247=89611.509

the number of families of four can one golf course provide water for :

[rounded to the nearest ten] 89610.

:)

Anastaziya [24]2 years ago
4 0

Answer:

<h2>Around 250 families can be provided with one golf course.</h2>

Step-by-step explanation:

Givens

  • A golf course uses 80 million gallons of water daily.
  • A family of four uses 325,851 gallons of water per year.

This situation can be described by the following equation

325,851x=80,000,000

Where x indicates the number of families that could use the 80 million galons of water.

Let's solve for x

x=\frac{80,000,000}{325,851}\\ x \approx 250

Therefore, around 250 families can be provided with one golf course.

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Question 1

Total budget = 180 + 475 + 15 + 50 + 65 + 25 + 150 + 30 = $990
Real spending = 182 + 475 + 12 + 65 + 68 + 12.50 + 150 + 36  = $1000.5

Mae Green didn't stay within the allocated budget

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Question 2

Eleanor:
Income = 380.48
Spending = 16.50

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Income = 120 + 13.65 + 100 = 233.65

Total income = 233.65 + 380.48 - 16.50 = 597.63

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Question 3

Total spent = 540 + 48.55 + 34.15 + 12.80 + 18.95 + 38.60 + 2 + 6.50 = 701.55

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Question 4 

Marie's new balance = 250.65 - [21.95+48.50+75.60] + 55 = $159.50

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Question 5

[235/825] × 100 = 28.48%
4 1
2 years ago
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The time for a professor to grade a student's homework in statistics is normally distributed with a mean of 12.6 minutes and a s
Rus_ich [418]

Answer:

37.23% probability that randomly selected homework will require between 8 and 12 minutes to grade

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 12.6, \sigma = 2.5

What is the probability that randomly selected homework will require between 8 and 12 minutes to grade?

This is the pvalue of Z when X = 12 subtracted by the pvalue of Z when X = 8. So

X = 12

Z = \frac{X - \mu}{\sigma}

Z = \frac{12 - 12.6}{2.5}

Z = -0.24

Z = -0.24 has a pvalue of 0.4052

X = 8

Z = \frac{X - \mu}{\sigma}

Z = \frac{8 - 12.6}{2.5}

Z = -1.84

Z = -1.84 has a pvalue of 0.0329

0.4052 - 0.0329 = 0.3723

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7 0
2 years ago
A set of data has a mean of 56.1. The data follows a normal distribution curve and has a standard deviation of 8.2. Find the pro
Whitepunk [10]
Given that mean=56.1 and standard deviation=8.2, P(x>67.5) will be found as follows:
The z-score is given by:
z=(x-μ)/σ
thus the z-score will be given by:
z=(67.5-56.1)/8.2
z=11.4/8.2
z=1.39
thus
P(z=1.39)=0.9177
thus:
P(x>67.5)=1-P(z>0.9177)
=1-0.9177
=0.0823
Answer: A. 0.0823
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