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mixer [17]
2 years ago
7

in which place is the digit in the number 5341 that would be changed to form 5841? how do the values of the two numbers compare

Mathematics
2 answers:
Snezhnost [94]2 years ago
6 0
The hundreds place!!!!
Vsevolod [243]2 years ago
4 0

the hundreds place

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Lin read for x minutes, and Elena read for more than that. Write an expression for the number of minutes Elena read. Only use de
Vikentia [17]
<h2>Explanation:</h2><h2 />

In this exercise, we know some facts:

  • Lin read for x minutes.
  • Elena read for more than that.

The problem tells us nothing about the number of minutes Elena read more than Lin. However, let's say Elena read one-third more than the number of minutes Lin read. Therefore:

<u>For Lin:</u>

Number \ of \ minutes \ Lin \ read=x

<u>For Elena:</u>

Number \ of \ minutes \ Elena \ read=x+\frac{1}{3}x \\ \\ Number \ of \ minutes \ Elena \ read=\frac{3x+x}{3} \\ \\ Number \ of \ minutes \ Elena \ read=\frac{4x}{3} \\ \\ Number \ of \ minutes \ Elena \ read=\frac{4x}{3} \\ \\ \\ By \ using \ decimals: \\ \\ Number \ of \ minutes \ Elena \ read \approx 1.33x

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2 years ago
Mr.Hollins determines that he gives away $800 each month. If he gives away 16% of his budget, how much is his overall budget?
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\frac{800}{x}  = \frac{16\%}{100\%}  \\  \frac{80000}{16}  =  \frac{16x}{16}  \\ 5000 = x
5 0
2 years ago
Which of the following rational functions is graphed below?
AlekseyPX

Answer:

The rational function that is graphed is B

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2 years ago
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In a race, Car #1 went an average of 165 miles per hour for x hours before dropping out. Car #2 went an average of 175 miles per
Akimi4 [234]
When you think about it. It's actually quite easy.
The number are the amount of miles, and the variables are the amount of hours. So we would just have to multiply them. So, by putting the number together we would be able to multiply them once we have the numbers for the variables. Since we dont have them, we can just make the inequality. It says that car 1 traveled at LEAST that of car 2. Showing that car 1 may have traveled farther. SOOOOO........ the inequality should look like this:

165x <span>≥ 175y</span>
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2 years ago
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An ostrich can run 6 mph faster than a giraffe. An ostrich can run 7 miles in the same time that a giraffe can run 6 miles. Find
LUCKY_DIMON [66]

NOTE THIS IS AN EXAMPLE:

Let t = time, s = ostrich, and g = giraffe.

Here's what we know:

s = g + 5 (an ostrich is 5 mph faster than a giraffe)

st = 7 (in a certain amount of time, an ostrich runs 7 miles)

gt = 6 (in the same time, a giraffe runs 6 miles)

 

We have a value for s, so plug it into the first equation:

(g + 5)t = 7

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Isolate g so that we can plug that variable value into the equation:

g = 6/t

so that gives us:

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Now that we have a value for time, we can plug them into our equations:

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Check by imputing into the second equation:

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