Answer:
D.Competitive inhibition will decrease because the proportion of the active sites occupied by substrate will increase.
Explanation:
Methyl alcohol is a competitive inhibitor of ethyl alcohol. This means that both of them compete with each other for the same enzyme (ADH). Methyl alcohol leads to poisoning because it is converted to toxic formaldehyde in body. It can be treated by increasing the concentration of ethyl alcohol.
More ethyl alcohol (substrate) will reduce the competitive inhibition by methyl alcohol (inhibitor). This will happen because a substrate needs active sites on an enzyme to attach to it. If ethyl alcohol is increased in concentration, it will occupy more active sites and their availability to methyl alcohol will be reduced. Thus, the enzyme will not be able to act on methyl alcohol.
Answer: 3. The half- life of the isotope must be long enough to capture the age of the rock. and
4. their should be more than one unstable isotope.
In radioactive dating proces, the parent isotope is in unstable state which undergoes decay process to give stable daughter isotopes. Half-life is the amount of time it takes for half of the parent isotopes to decay. The rock dating requires a long lived parent isotope so that it can capture the exact rock age.
One rock when get decayed in the daughter isotope other will be available identify the age.
Answer: Option B
Explanation: First we should understand the role of enzyme and acid here. Pepsin is an enzyme which will break down proteins into simple monomers (like amino acids). And, acid causes digestion which means it will break down the protein into its respective elements and compounds. Water will act as a control in this experiment.
Option B is correct because it has all three criteria- 1. Control [water + protein] 2. With enzyme [egg white + pepsin] 3. With acid and enzyme
So this will give us an idea whether pepsin alone is breaking down the protein or digesting it. And there would be difference in test tube B and C. So this will clear the difference.
Option A is incorrect because it has not mentioned any different test tube for checking what happened with the protein. And, Option C is incorrect because mass of egg white will remain same after digestion also.
I believe it is B. Growing
Hope this helps!
