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2 years ago

What is the domain of the function y = 2 StartRoot x minus 5 EndRoot?

Mathematics

2 answers:

Dennis_Churaev [7]2 years ago

3 0

Answer:

Domain: $x\geq5\ or\ [5,\infty)$

Step-by-step explanation:

Given:

The function is given as:

$y=2\sqrt{x-5}$

A function is just like a machine that gives an output for a given input.

The input to a function is called the domain of a given function. The output of a function is called its range.

The variable that is used to represent the domain is 'x' and the range is represented by the variable 'y'.

So, the domain is the independent variable and range depends on the values of the domain.

Now, the given function is a square root function. From the definition of square root function, we know that, the terms inside the root must be 0 or greater than 0. Therefore,

$x-5\geq 0$

Now, solving for 'x', we add 5 on both sides. This gives,

$x-5+5\geq 0+5\\\\x\geq 5$

Therefore, the values of 'x' must be greater than or equal to 5.

Hence, the domain of the function are all values of 'x' which are either 5 or greater than 5.

Domain: $x\geq5\ or\ [5,\infty)$

LUCKY_DIMON [66]2 years ago

3 0

Answer:it’s C my guy

Step-by-step explanation:

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Of all the weld failures in a certain assembly, 85% of them occur in the weld metal itself, and the remaining 15% occur in the b

Aloiza [94]

Answer:

a.) 0.1028

b.) 0.6477

c.) 0.0388

d.) 3

e.) 2.55

Step-by-step explanation:

Forming a binomial Probability distribution

n = 20

Probability of success for Weld metal failure = 85%

Probability of success for base metal failure = 15%

We use the probabilit distribution formula of combination to solve the problem.

P(x=r) = nCr * p^r * q^n-r

a.) if exactly 5 are base metal failures, then p = 15 and our solution becomes:

P(x=5) = 20C5 * 0.15^5 * 0.85^15

P(x=5) = 0.1028

b.) probability that fewer than 4 are base metal failure= P(x=0) + P(x=1) + P(x=2) + P(x=3)

P(x=0) = 20C0 * 0.15^0 * 0.85^20 = 0.0388

P(x=1) = 20C1 * 0.15¹ * 0.85^19 = 0.1368

P(x=2) = 20C2 * 0.15² * 0.85^18 = 0.2293

P(x=3) = 20C3 * 0.15³ * 0.85^17 = 0.2428

Probability that fewer than 4 are base metal failures becomes: 0.038 + 0.1368 + 0.2293 + 0.2428 = 0.6477

c.) probability that none of them are results of base metal failure = P(x=0). As earlier calculated,

P(x=0) = 0.0388

d.) mean of base metal failures = np = 20*0.15 = 3

e.) standard deviation of base metal failures = √np(1-p)

=3 * (1 - 0.15) = 3 * 0.85

= 2.55

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2 years ago

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kifflom [539]

Answer:

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Step-by-step explanation:

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