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Mars2501 [29]
2 years ago
10

3x5 – 7x4 + 6x2 – 14x

Mathematics
1 answer:
Andreas93 [3]2 years ago
4 0

Question is Incomplete; Complete question is given below;

What is the completely factored form of 3x5 – 7x4 + 6x2 – 14x.

Answer:

The Complete factorized form of given equation is x((x^3+2)(3x-7)).

Step-by-step explanation:

Given:

3x^5-7x^4+6x^2-14x

We need to factorize the above equation:

Solution:

On Solving the above equation we get;

Step 1:

First we will take a common factor which is 'x' so the equation will become as;

x(3x^4-7x^3+6x-14)

Step 2:

Now we will Rewrite the above equation so as to factorize the same we get;

x(3x^4+6x-7x^3-14)

Step 3:

Now we take 3x common factor from first 2 terms we get;

x(3x(x^3+2)-7x^3-14)

Step 4:

Now we will take 7 as common factor from last 2 terms we get;

x(3x(x^3+2)-7(x^3+2))

Step 5:

Now we can see the common factor between the 2 terms is x^3+2;

x((3x-7)(x^3+2))

Hence The Complete factorized form of given equation is x((x^3+2)(3x-7)).

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Step-by-step explanation:

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dmitriy555 [2]
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Alicia measured 1/4 yard of the blue diamonds fabric and 5/6 yard of the yellow bonnets fabric to make a quilt. rename each leng
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2 years ago
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Given △DEF, which is not equal to cos(F)? sin(F). sin(D). tan(F). cos(D)
valentina_108 [34]

Answer: The correct option is tan(F).

Explanation:

In the given figure the triangle is a right angle triangle because \angle E=90^{\circ}.

It is also given that DE=EF=5 and DF=5\sqrt{2}.

Since it is an isosceles right angle triangle, therefore the value of perpendicular and base is same for both angles D and F, which is 5.

\cos (F)=\frac{Base}{Hypotenuse} =\frac{5}{5\sqrt{2}} =\frac{1}{\sqrt{2}}

The value of cos(F) is \frac{1}{\sqrt{2}}.

\sin (F)=\frac{Perpendicular}{Hypotenuse} =\frac{5}{5\sqrt{2}} =\frac{1}{\sqrt{2}}

The value of sin(F) is \frac{1}{\sqrt{2}}.

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The value of sin(D) is \frac{1}{\sqrt{2}}.

\tan (F)=\frac{Perpendicular}{Base}=\frac{5}{5} =1

The value of tan(F) is 1. Which is not equal to \frac{1}{\sqrt{2}}.

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The value of cos(D) is \frac{1}{\sqrt{2}}.

Therefore, the value of tan(F) is not equal to the value of cos(F), so the correct option is third.

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2 years ago
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