Answer:
The maximum revenue is $900, obtained with 30 people
Step-by-step explanation:
Naturally, the answer should be a number equal or higher than 20, because up to 20 persons, each one pays the same. Lets define a revenue function for x greater than or equal to 20.
f(x) = x*(40-(x-20)) = -x²+60x
Note that f multiplies the number of persons by how much would they pay (here, assuming that there are more than 20).
f is quadratic with negative main coefficient and its maximum value will be reached at the vertex.
The value of the x coordinate of the vertex is -b/2a = -60/-2 = 30
for x = 30, f(x) = 30*(40-(30-20))=30*30=900
So the maximum revenue is $900.
G(h) h
12 3
8 5
4 7
0 9
Equation of the line:
slope = [12-0]/[3-9] = 12 / -6 = -2
g / [h - 9] = -2
g = -2(h-9)
g = -2h + 18
g = 18 -2h
Filling the tank ==> h = 0
g = 18 - 2(0) = 18
Answer: first option g = 18 -2 h; 18
Let x = weight of adult meerkat, y=weight of baby meerkat, Find y.
x=0.776 kg
y+7.47hectogram=x=0.776
Since 1 hectogram = 0.1 kg,
Therefore the weight of baby meerkat is, y= 0.029 kg
890×(1+0.187÷12)^(12)−890×(1+0.125÷12)^(12)=63.61....answer
