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Ira Lisetskai [31]
2 years ago
12

Both Marianne and Bill examined the same set of qualitative data collected from couples in a study designed to understand relati

onship stress. Interestingly, the themes that emerged from the data were not consistent across the two researchers. Of the following, which is the most likely reason for the discrepancy? a. The data were not valid. b. The coding scheme was not reliable. c. Qualitative analysis is too subjective. d. The patterns in the data were too subtle.
Business
1 answer:
slava [35]2 years ago
7 0

Answer: B. The coding scheme was not reliable.

Explanation: The most likely discrepancy for the of this study/research is the coding system, a coding system is an analytical tool used to categorize samples or treatments in order to effectively enhance the research or study  and to give correct results. Coding systems are also used in computer analysis for effective result presentation. Coding can be used in quantitative analysis such as Questionnaire results and in qualitative in the case of interview transcripts.

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A speed boat bought for $13,000 depreciates at 10% per annum compounded continuously. What is its value after 7 years? Round the
xz_007 [3.2K]

Answer:

$3,900

Explanation:

A speed boat bought for $13,000 depreciates at 10% per annum compounded continuously. What is its value after 7 years?

Round the answer to nearest dollar.

Amount of depreciation per annum =  13,000 x 10% = $1,300

Amount of depreciation in 7 years = 1,300 x 7 = $9,100

Value of Speed boat after 7 years = 13,000 - 9,100 = $3,900

6 0
2 years ago
Order the bond types below from lowest to highest risk of default.
Ymorist [56]

Answer:

According to the risk of default from lowest to highest:

1. U.S. Treasury bonds.

2. Corporate bonds.

3. Junk bonds

Explanation:

Bonds are ways through which a governments and corporations are able to raise money in-order to finance the big projects.

It is issued to the public through a mapped out auction based in months or years validity. <em>And, by buying a bond, you're giving the issuer a loan, and they agree to pay you back the face value of the loan on a specific date, and to pay you periodic interest payments.</em>

4 0
2 years ago
Read 2 more answers
Suppose that your colleague has accidentally spilled coffee on his laptop and the file containing your firm\'s cost data has bee
Wittaler [7]

Solution:

Q      MC       FC      VC     TC      AFC     AVC     ATC

0       NA       50        0       50       NA      NA       NA

1        50      50       50      105       50       50      105

2        19       50      64       104       20       32       52

3       85        40      149      189    13.33    49.67  63.00

4      223       40      372     412       10        93        103  

TC=FC+VC

FC=40

VC=TC-FC

MC=change in TC

AFC=FC/Q

AVC=VC/0

ATC=TC/0

a) TC when 0=0 = 40 because FC = 40 remains constant and the firm still incurs a total cost equal to its FC when it produces zero output.

b) MC for first unit = 45

c) ATC of 3rd unit = 63

d) AVC for 4th unit = 93      

6 0
2 years ago
An industrial plant needs to make 100,000 parts per month to meet demand. Each month contains 20 working days, each of which all
Ratling [72]

Answer:

Part A:

Workers Needed=20.833≅21

Part B:

Productivity of individual worker=2.0833 parts/hour

Part C:

Multifactor productivity=0.0832 Parts/$

Explanation:

Part A:

Total parts =100,000

Workers needed= Total parts/(Parts per hour* hours per shift*Total Shifts)

Worker\ needed=\frac{100000}{10\ Parts/hour*8\ hours/shift*60\ shifts/worker} \\Workers\ needed= 20.833

Workers needed=20.833≅21

Part B:

Productivity of individual worker:

Productivity\ of\ individual\ worker=\frac{100000}{100\ workers*8\ hours/shift*60\ shifts/worker} \\Productivity\ of\ individual\ worker=2.0833\ parts/hour

Part C:

Total cost of material= $10*100,000=$1,000,000

Capital Costl= $100,000

Total labor Cost=21\ workers*8\ hours/shift*60\ shifts/worker*\$10/hour

Total labor Cost=$100,800

Multifactor productivity=Total Parts/(Total cost of material+capital cost+Total labor Cost)

Multifactor\ productivity=\frac{100000}{\$1,000,000+\$100,000+\$100,800} \\ Multifactor\ productivity=0.08324\ Parts/\$

3 0
2 years ago
During April, the first production department of a process manufacturing system completed its work on 365,000 units of a product
Zigmanuir [339]

Answer  

The answer and procedures of the exercise are attached in a microsoft excel document.  

Explanation  

Please consider the data provided by the exercise. If you have any question please write me back. All the exercises are solved in a single sheet with the formulas indications.  

Download xlsx
5 0
2 years ago
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