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otez555 [7]
2 years ago
5

A deli sells meat and cheese by the pound. The expression 7.99m + 5.99c represents the total cost of m pounds of mest and c poun

ds of cheese.
Which statement is true?

A. Each pound of cheese costs $5.99
B. Each pound of meat costs $5.99
C. The total cost for c pounds of cheese is $7.99
D. The total cost for m pounds of meat is $7.99
Mathematics
1 answer:
LenaWriter [7]2 years ago
6 0
Statement A is correct.

7.99m is the unit rate for how much you will pay for each pound of meat.

5.99c is the unit rate for how much you will pay for each pound of cheese.
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The vertices of polygon ABCD are at A(1, 1), B(2, 3), C(3, 2), and D(2, 1). ABCD is reflected across the x-axis and translated 2
Lana71 [14]

-- Reflecting across the x-axis makes all the x-coordinates the negative of
what they were before the reflection.  The y-coordinates don't change.

-- Translating 2 units up makes all the y-coordinates 2 greater than
they were before the translation.  The x-coordinates don't change.

You didn't give us a list of new coordinates, so there's nothing
to match with.
8 0
2 years ago
A doctor recommends a two-step process to treat a rare form of pancreatic cancer. The first method is successful 80% of the time
Rudiy27

Answer:

The answer is 15%.

Step-by-step explanation:

The probability that:

  • Both treatments are successful:

       80% x 90% = 72%

  • The first method is a success, but the second one is not:

        80% x (1 - 90%) = 8%

  • The first method is not successful, but the second one is:

        (1 - 80%) x 25% = 5%

  • Both treatments are unsuccessful:

        1 - (72% + 8% + 5%) = 15%

5 0
2 years ago
Isoke is solving the quadratic equation by completing the square.10x2 + 40x – 13 = 0 10x2 + 40x = 13 A(x2 + 4x) = 13What is the
Elina [12.6K]

we have

10x^{2} + 40x - 13 = 0

Group terms that contain the same variable, and move the constant to the opposite side of the equation

10x^{2} + 40x =13

Factor the leading coefficient

10(x^{2} + 4x) =13 ----------> the value of A is 10

Complete the square. Remember to balance the equation by adding the same constants to each side

10(x^{2} + 4x+4) =13+40

10(x^{2} + 4x+4) =53

Rewrite as perfect squares

10(x+2)^{2} =53

10(x+2)^{2} =53  \\ (x+2)^{2} =\frac{53}{10} \\ \\ x+2=(+/-)\sqrt{\frac{53}{10}}  \\ \\ x1=-2+\sqrt{\frac{53}{10}}\\ \\ x2=-2-\sqrt{\frac{53}{10}}

therefore

the answer is

the value of A is 10

3 0
2 years ago
Read 2 more answers
An orange is shot up into the air with a catapult. The function h given by h(t)=15+60t-16t^2 models the orange’s height, in feet
Studentka2010 [4]

Complete question is:An orange is shot up into the air with a catapult. The function h given by h(t) = 15 + 60t - 16t² models the orange’s height, in feet, t seconds after it was launched.

Select all the true statements about the situation.

Options:

1. The domain of function h only contains values greater than or equal to 0.

2. The orange is at the same height 1 second after launch and 2 seconds after launch.

3. After 3 seconds, the orange has hit the ground.

4. The orange is 15 feet above the ground when it is launched.

5. The value t = 10 does not belong to the domain of h.

Answer:

Option 1 - True

Option 2 - False

Option 3 - False

Option 4 - True

Option 5 - True

Step-by-step explanation:

Looking at the options,

-The domain is the x or t value and it is time. Now, time can only be positive or greater than or equal to zero i.e. t ≥ 0. Thus, option 1 is true.

- At t = 1 second;

h = 15 + 60(1) - 16(1)²

h = 15 + 60 - 16 = 59 ft

Also, at t = 2 seconds;

h = 15 + 60(2) - 16(2)²

h = 15 + 120 - 64 = 71 ft

So,value of h is not the same at t = 1 and t = 2. Thus, option 2 is not true.

- The orange will hit the ground when h(t) = 0.

However, at t = 3;

h(t) = 15 + 60(3) - 16(3)²

h(t) = 51 ft

h(t) is not equal to zero at t = 3, so option 3 is false

- when the orange is launched it is at time t = 0.

Thus,

h(0) = 15 + 60(0) - 16(0)²

h(0) = 15 ft

So option 4 is true.

- At t=10, h(t) = 15 + 60(10) - 16(10)²

h(10) = -985

This means the orange would be below ground level and thus doesn't belong to the domain of h, so option 5 is true.

6 0
2 years ago
Daniel wants to predict how far he can hike based on the time he spends on the hike. He collected some data on
horsena [70]

Answer:

Daniel can read his data and refer to line as best line of fit and estimate an average per set of hours.

Step-by-step explanation:

A line of fit draws a solid conclusion to the average for the hours spent during the amount of indicated hours. We draw a line of fit central fit and aim similar centrality as that similar results of the mean (without working out the mean we can draw a line perpendicular to the number of mean, but in line of fit we go central to all the descending or cascading results to include all results but just using one line), with one further consideration and that is balance if anything sticks out from the norm ie) weather conditions including data, we suggest if there is nothing to weigh the line of fit to a balancing outcome that shows the opposite of kilometres walked (eg. extreme higher mileage within the hour/s) then it may just alter the line a fraction of how many treks he did, but not in data less than 30 entries. Have attached an example where they classify in economics something outside the norm is called a misfit. Daniel can read his data and refer to line as best line of fit and estimate an average per set of hours. Here on the attachment you can read any misfit info and use the line coordination perpendicular to guide the indifference, the attachment shows it is not really included in the best line of fit as other dominating balances have occurred and therefore we have a misfit, all whilst using best line of fit to balance everything fairly.

7 0
2 years ago
Read 2 more answers
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